Please help answering 5.10-5.19 please and thank you

Number positive of Community prevalence Absolute percentage Unadjusted risk ratio pvalue Adjusted risk ratio" pvalue total respondents (95% CI) o What value is E? change from baseline (95% CI) (95% CI) 95% CI) Hookworm Q5.15 12-month assessment School-based deworming 1284 of 7957 16-1% (12.1 to 20.1) -2-4% (-10.9 to 6.1) 1 (ref) 1 (ref) o What value is F? Annual community-wide 984 of 8355 11-8% (9-0 to 14-6) 6-1% (-13-6 to-1-3) 0.73 (0-52 to 1-03) 0-77 (0-65 to 0-91) treatment Biannual community-wide 836 of 8177 10-2% (7-6 to 12.9) -10-4% (-15-5 to-6-0) 0-64 (0.45 to 0.92) 0-04 0-65 (053 to 0.78) 20-001 Q5.16 Using the 2x2 table above, calculate the unadjusted ("crude") risk ratio of hookworm infection in treatment 4-month assessment School-based deworming 972 of 7058 13-8% (10.5 to 17.0) 48% (-13-0 to 3.5) 1 (ref) this study. Do not round intermediate steps. Only round the final answer to the nearest hundredth. 1 (rel) Annual community-wide 597 of 7446 8-0% (6 0 to 10-1) -9-9% (-16-8 to-3-0) 0.59 (0.42 to 0-83) 0-64 (0-52 to 0-78) treatment o Final answer: Biannual community-wide 453 of 7281 6.2% (4.9 to 7:5) 14-4%% (-21-4 to-7:4) 0-46 (0.33 to 0.63)