Please help Asap with grade 12 student knowledge and show step-by-step. Thank you. ?

1. Q#1. A neutral Helium-4 atom [ ] has: (1) a nucleus made up of 2 neutrons and 2 protons, and it also has (2) two orbitting electrons at some distance out from the nucleus in a probability distribution cloud (to which one can assign an average orbital radius for the sake of classical physics determinations). If this Helium atom loses one of its two electrons due to ionization, then it becomes a He charged cation: [ ] . If this Helium \"+le cation\" additionally loses its one remaining electron due to further ionization, then it becomes a +2e charged cation: [ ], also sometimes called an "alpha particle" or Helium nucleus. We can assume the originally neutral Helium atom's orbital radius for either electron as 1.40 A (1 A = l Angstrom = 10710111) or 0.140 nm. We will use this same radius for the one-electrononly +1e cation: . 1(a) The rst ionization removal of an electron means removing an electron charge (-le) to an innite distance away from what has now become a +1 e cation charged version of what's left of the original Helium atom, [ ] : (i) determine the total ionization energy (J) required to remove this rst electron to a theoretically innite distance away from the [ ] cation it leaves behind, and (ii) determine also the electric potential difference or voltage change involved (J/C). 1.(b) Repeat part (a)((i) and (ii)), but for the removal of the second electron to an innite distance away from what has now become the +2e cation charged version of what's left of the original Helium atom, . l.(c) Compare the ionization energies and voltage changes for the rst ionization (see part (a)) versus the second ionization (see part (b)). What do you notice? How can you explain that this result makes sense given the nature of your calculations? What is the key difference between your calculations in part (a) versus part (b)