Please help Asap with grade 12 student knowledge and show step-by-step. Thank you.
Q#2. A charged small plastic bead is suspended under the center of a smooth charged plate (see below in part (a) -- (note: this plate here will become the top plate of a pair ofparallel plates when a 'bottom plate' is brought in later on, and then the parallel plates will be hooked up to a power supply). This plate's horizontal extent above the bead is very large compared to the size of the bead. Assume a vacuum so there is no air interference. Later (see below), after a bottom plate is brought in directly under the bead and what now becomes, effectively, the 'top plate', a voltage will, at some point, be placed across the plates. The voltage across these parallel plates when the power supply is turned on will be 0.7199 kV, with the top plate positively charged and the bottom plate negatively charged. These parallel plates have a gap between them of perpendicular length 25.40 cm. The bead has a +3204 nC positive charge on it and has a mass of 28.35 mg. o-Lmr this is the only Plate for Paris (a) and |:I (b); bottom plate gets added in later on . he charged small plastic bead ottom late: this is only added in later, my parts (a) and (b); the top M bottom plates are both present for parts (c) (d) and (e) 2.(a) Assume the charged bead induces a charge of opposite sign but the same magnitude as is on the plastic bead, and this induced charge occurs in a small localized area of the top plate, directly above the charged bead. How far below the top plate is the bead? 2.(b) How does the gravitational potential energy calculation for the bead compare to its electric potential energy (can think also of work-related energy calculations)? H Consider this comparison for a linear displacement from the current 'at rest' bead-location to a position directly below it where the surface of the bottom plate will eventually be located when it is added to the overall parallel plates arrangement. 2.(c) If the bottom plate is added and the voltage is suddenly turned 'ON', what would the M velocity vector be for the bead: (i) if we have the normal gravity found at Earth's surface? (ii) if we have an environment of weightlessness (i.e. no external source ofgravity at all)? Assume the bead starts from the same initial 'at rest' position determined in (a). [ Also, assume that the charge originally induced by the bead {see above), in a small area of the lower surface ofthe top plate above the bead, disappears completely as soon as the power supply is turned on. Furthermore, assume that the bead, ifit now starts moving, is eventually stopped by either the top plate or the bottom plate ofthe parallel plates arrangement. lfthe bead makes it to one ofthe plates, you are calculating its 'impact velocity' -- ie the head's vcloc1ty just before impact with whichever plate it hits. ] 2.(d) If the voltage across the parallel plates is 'OFF', what would the nal velocity vector be for the bead? Assume we have the usual gravitational acceleration found at Earth's surface and that there is no induced charge from the bead. Assume the bead starts from the same initial 'at rest\" position determined in (a). [ Again, assume that the bead is eventually stopped by one ofthe two parallel plates. When the bead makes it to one of the plates, you are calculating its 'impaet velocity' -- i.e. the bead's velocityjust before impact with whichever plate it hits. ] 2.(e) How do the 3 above bead-impact-velocity results (i.e. from part (c)((i) and (ii)) and part (d)) compare? Explain any connection between the determinations you made in parts (0) and (d). Include a labelled diagram to help with your explanations
