Please help determine the normal force and acceleration

30N force is applied on 6 kg object which is at rest on a smooth horizontal table. the normal force acting on the object and its acceleration for following cases. I. Applied force is horizontal. $ 58. 8N W= ( 6 )( 9.8 ) = 58.8 304 6 kg f = ma 158 8 N 58. 8= 6 a 5m/s II. 30N force is directed 30 above horizontal W= mg (cos30) = 50 30 cas 30 W= macos ? III. 30 N force is directed 30 below horizontal. W= mg (cessgo ) (6) (30 / C W = 30 W= 156N 25.98 = 16) a W=mg + cos 30 4.33 = 9 59. 7