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Please help I'm very stuck in this (3) It can be shown that g(x) s x2cos ( sh(x). We can evaluate lim x2cos () using

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Please help I'm very stuck in this

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(3) It can be shown that g(x) s x2cos ( sh(x). We can evaluate lim x2cos () using the Sandwich theorem X -0 (Squeeze theorem). Find g(x), h(x) which satisfy the above inequality and converge to the same limiting value as x goes to 0. Use your findings to evaluate lim x2cos x +0

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