Please help in a simple form that a college student understand.

One method to establish the center of mass of a one dimensional object, an object that only has length and a negligible thickness like a pencil or meter stick, is to find the point at which you can support it so that it balances horizontally. Consider the board used in a seesaw as diagrammed below. The fulcrum is the support about which the seesaw would be able to rotate if one or two people were to mount it. The number line is present to define the location of the fulcrum.

1. Center of Mass One method to establish the center of mass of a one dimensional object, an object that only has length and a negligible thickness like a pencil or meter stick, is to nd the point at which you can support it so that it balances horizontally. Consider the board used in a seesaw as diagrammed below. The fulcrum is the support about which the seesaw would be able to rotate if one or two people were to mount it. The number line is present to dene the location of the fulcrum. 3:20 a: a. Where should the fulcrum be placed to balance the seesaw horizontally? Explain your conclusion. b. Let's consider a more interesting scenario where two unequal masses m2 and m;; are placed on the seesaw as diagrammed below. Suppose that we want to place the fulcrum at the location which will allow the system to balance horizontally, Where is that point? In other words where is the center of mass of this system located? One approach is to simply assume a location, as we have below, and then solve for 930M such that the net torque is zero about the fulcrum. Make a complete and properly labeled extended force diagram for the seesaw. fulcrum _ 0 .73 33 332 1130M 1131 933 c. In your extended force diagram, include an \"x" to represent the axis of rotation at the fulcrum, and nd the position for each force that acts on the seesaw. cl. Show that the net torque about the fulcrum is given by 27': mgg(a:0M $2) mlg(:c1 170M) m3g($3 xcM) = 0. e. Solve for $60M. Use it to explain how it relates to the denition of center of mass traditionally given in introductory textbooks: 211ml; 21m1+22m2+...+zlmi mCM : Ezmi : m1+m2+...+mi