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Please help Let f(a) = 3 - |2 - 3| on [0, 6]. f (0 ) = f (6) = Find c such that f'

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Let f(a) = 3 - |2 - 3| on [0, 6]. f (0 ) = f (6) = Find c such that f' (c) = 0 If Rolle's Theorem does not apply, enter DNE Question Help: Video Submit Question Consider the function f(x) = 4x - 3x on the interval [ - 2, 2]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists at least one c in the open interval ( - 2, 2) such that f' (c) is equal to this mean slope. For this problem, there are two values of c that work. The smaller one is and the larger one is Question Help: Video Submit Question Consider the function f(x) = - on the interval [3, 9]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists a c in the open interval (3, 9) such that f' (c) is equal to this mean slope. For this problem, there is only one c that works. Find it. Question Help: Video Submit

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