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Match the differential equation with its direction field. y' = 5(x + y)- 1 1 1 1 - 8 1 12* 1II 1 1 1 1III 1 1 N O-2 / 0.6 / - 0.6T - 0.4 Q2 - 1 P.I 11 1 -Q.61 1-10.4 1 +012 1 1 0.2- - 0.4 / /0,6 -0.6- --0.4 - -0.2- 0.2 0.4 0.6 0.2 OGive reasons for your answer. The slopes at each point are independent of x, so the slopes are the same along each line parallel to the x-axis. Note that for y = 5, y' = 0. O y' = 5(x + y) - 1 = 0 on the line y = -x + 1/5, and y' = -1 on the line y = -x. O y' = 5(x + y) - 1 = 0 on the lines x = 0 and y = 0, and y' > 0 for 0