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Please help me answer the following question. Thank you Question 11 The options for part b are: Reject/ do not reject H0. There is sufficient/

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Please help me answer the following question. Thank you

Question 11

The options for part b are: Reject/ do not reject H0. There is sufficient/ insufficient evidence to conclude that there is a difference in the population means of the groups.

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FE LIFT IFE LT HE LIFE IVE CHE COT IFT IST ME IF OF'T FIT COF FIT OF'S OF FIT HE THE NIT LL'Z ICE OF E LIT WT CH'Z IFE LOT IFE OF E OF'E LIT IFT IT OL'E EN'S 01 IVE OFY LIT SEE LET 1019 ITY HF OF'S OIT IFE PUT IFT IFE 991 FIT 91 1 IFE IFY NT IFE OFF CE'S WE OFF LYF ICT 10'01 OF F CF'S IN'S EO 9 T.in SETI LIFE SL'EI 9101 WTI LE FI 5491 DE 65 Con da dive Probabilities 30.19Upper-Till Ann - i,Out Sumer Mon f Denominator 10 16,21 1.001 19850 1949.30 149.30 149 10 5955 47.AT 46.19 31JS 23.15 31.14 30 00 15.56 1451 13.17 1250 12.70 1454 9.34 4.13 16.24 7.73 14.69 11.04 T.M TH 721 13.61 10 12.2 6.10 5.54 5.42 11.75 7.31 12 1137 LIT 1 1.06 14 10.50 7.70 J.N 15 1.31 4.M 3.73 LII 7.15 6.16 4.78 3.61 351 17 LET 5.27 1.59 L.IT 3,27 LII 3,70 6.71 436 1.75 3.13 1.71 1.60 9.55 4.30 34 1.30 654 2.45 434 4.74 2.83 IN LOT 5.34 3,71 151 1.32 3,12 3.78 154 2.71 2.10 1.75 130 Why nondani or 10 20b. What is your statistical decision? E H0. There is |:I evidence to conclude that there is a difference in the population means of the groups. Homework: Module 10- One-way ANOVA Sa Score: 0 of 1 pt 11 of 14 (11 complete) HW Score: 59.1%, 8.27 of 14 Instructor-created question Question Help The ANOVA summary table for an experiment with four groups, with six values in each group, is shown to the right. Complete parts (a) through (d) below. Degrees of Sum of Mean Square Source Freedom Squares Variance F Among C-1=3 SSA = 180 MSA = 60 FSTAT = 2.00 groups Within 1- C=20 SSW = 600 MSW = 30 groups Total n - 1=23 SST = 780 Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. a. At the 0.05 level of significance, state the decision rule for testing the null hypothesis that all four groups have equal population means Determine the hypotheses. Choose the correct answer below. O A. HO- M1 = 12 = " . . = H4 OB. HO H1 = 12= . . . = 16 Hy: Not all the means are equal. O C. Ho M1 = H2= ". . = 16 OD. HO H1 = 12 = . . . = HA H1: Not all the means are equal. Hy: My $ 12 # . . . # HA Find the test statistic. FSTAT = (Round to two decimal places as needed.) Determine the critical value at the 0.05 level of significance Fa =(Round to two decimal places as needed.) b. What is your statistical decision

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