please help me asap.

In the chemical reaction: Br2(g)+Cl2(g)2BrCl(g)Kp=0.150 If there is initially 0.500atm of BrCl and nothing else. What is the Kp expression in terms of x ? Kp=z2(0.3+2z)2Kp=z2(0.52)2Kp=z2(0.52z)Kp=a3(0.5z)2 Question 2 From Question 1, set up the ICE table. and determine the partial pressure (in atm) of BrCl at equilibrium. 0.209atm0.291atm0.418atm0.082atm