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Please help me code the following in: JAVA Please code in as simple way as possible and with comments so I can understand! Full points

Please help me code the following in: JAVA

Please code in as simple way as possible and with comments so I can understand!

Full points will be awarded, thanks in advance!

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2. In Excel, make a plot of velocity vs. time for a skydive case (the parameters of which are described below). Submit an image file of this plot (you can print/save the plot to an image format or scan a paper printout of your image). Velocity is on the y-axis and time is on the x-axis. a. Your image file can be PDF, JPG, TIF, or PNG. b. Please submit only one image file via Canvas. Do not email your instructor your work. C. Name your file Velocity.jpg (or whatever is the extension for the graphic format you're using). You must name your file this way If you're not sure how to make a plot of data written to a comma-separated value (CSV) file using Excel (or any other program), please give yourself extra time to see how to do this. Here are two links to start with: importing a CSV file in in Introduction to the Problem If you had physics before, you will recognize the problem of finding the velocity of a skydiver as similar to that of the fall of an object under the influence of gravity. However, unlike the case studied in most introductory physics courses, where air resistance is neglected, in the case of a skydiver, you cannot neglect air resistance. Thus, Newton's Second Law has two forces you have to account for: Rot-ma = Pravity-Far where m is the mass (kg) and a is the acceleration (m/s) of the skydiver. Note, in this and subsequent equations, we will assume that the positive x-direction (and thus the positive velocity and acceleration) points down towards the ground (As an aside, in a vacuum where we can neglect air resistance and gravity is the only force acting on the skydiver, we can neglect Fdrag and the above simplifies: Meaning, the acceleration of the skydiver(a) equals the acceleration of gravity at the surface of the Earth (g - 9.81 m/s2). Which makes sense))

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