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Question 1 1 pts When two red LEDs are connected in series with a resistor, as shown in the schematic below, how do the brightnesses of the 2 LEDs compare? D1 D2 PSB + Red Red 5 V R1 220 Q O It depends on the arrangement of the circuit. The brightness of D1 is greater than the brightness of D2. The brightness of D1 is approximately the same as the brightness of D2. The brightness of D1 is less than the brightness of D2.Question 2 3 pts Consider the brightness of each of the LEDs when two red LEDs are connected in series with a resistor and a shorting wire is connected across the second LED, as shown at D2 in the schematic below. Select all three of the following statements that apply. D1 D2 PSB + Red Red 5 V R1 220 Q O The brightness of D1 is greater than the brightness of D2. O D1 is brighter than it was before the shorting wire was added. O D2 does not visibly light. O D1 does not visibly light. O The brightness of D1 is less than the brightness of D2. D2 is brighter than it was before the shorting wire was added. O The brightness of D1 is approximately the same as the brightness of D2.Question 3 6 pts Consider how the circuit was effected by adding a shorting wire across D2, shown in the schematic below. Compare the color-coded schematics you were instructed to make in Steps 1 & 2. Select the best answer to each question below. You may collect further evidence to support your answers by using your voltmeter to measure the voltage across each component both before and after the shorting wire is added across D2. D1 D2 PSB Red Red 5 V R1 220 Q a.) How is the voltage across each of the components in the circuit changed when the shorting wire is added across D2? [ Select ] b.) How is the flow of current changed in the circuit by adding the shorting wire across D2? [ Select ] Select The path followed by the current no longer includes D2. Current is disproportionately redirected away from previous areas, where the energy is dissipated as excess heat. The current is the same as before, but D2 is no longer affected by the current and does not light up. c.) How does D2 affect the circuit after the shorting wire is added, as shown in the schematic D2 is burned out, because the shorting wire has almost no resistance.Question 3 6 pts Consider how the circuit was effected by adding a shorting wire across D2, shown in the schematic below. Compare the color-coded schematics you were instructed to make in Steps 1 & 2. Select the best answer to each question below. You may collect further evidence to support your answers by using your voltmeter to measure the voltage across each component both before and after the shorting wire is added across D2. D1 D2 PSB + Red Red 5 V R1 220 Q a.) How is the voltage across each of the components in the circuit changed when the shorting wire is added across D2? [ Select ] b.) How is the flow of current changed in the circuit by adding the shorting wire across D2? [ Select ] c.) How does D2 affect the circuit after the shorting wire is added, as shown in the schematic above? [ Select ] [ Select] D2 is still a red LED. Since the component has not been changed, its effect on the circuit has not changed. D2 uses more energy than before. D2 is no longer affecting the circuit. D2 has turned off, forcing current to flow through the jumper wire instead.Question 3 6 pts Consider how the circuit was effected by adding a shorting wire across D2, shown in the schematic below. Compare the color-coded schematics you were instructed to make in Steps 1 & 2. Select the best answer to each question below. You may collect further evidence to support your answers by using your voltmeter to measure the voltage across each component both before and after the shorting wire is added across D2. D1 D2 PSB + Red Red 5 V R1 220 Q a.) How is the voltage across each of the components in the circuit changed when the shorting wire is added across D2? [ Select ] Select] Voltage across D1 remains the same (red). Voltage across R1 also remains the same (blue). Only the voltage across D2 has changed (from orange to yellow). There is no longer voltage across D2. That voltage is now added to D1, which lights more brightly as a result. b.) How i D2 now has the same color on both sides, showing that there is no voltage across that LED. The total circuit voltage is unchanged, so the voltage across the other components is increased The PSB setting is unchanged, therefore the voltage across the circuit remains the same (5V). c.) How does D2 affect the circuit after the shorting wire is added, as shown in the schematic above? [ Select ]Question 4 3 pts What did you predict would happen if you shorted D1 instead of D2, and why. Remember that a valid prediction must include the reason for the expected outcome. Edit View Insert Format Tools Table 12pt Paragraph B IYA Q V T V V EVEV TO VX I P 0 words >Question 5 3 pts When you shorted D1 instead of D2, did the observed results match your prediction? If not, what differences do you observe and how might they be explained? Edit View Insert Format Tools Table 12pt v Paragraph BIUA &V T V 8 v EVEVEV TO BV VX H P O words > ::::Question 6 4 pts Why did the LEDs in this lab not burn out when they were shorted? Your explanation should include descriptions of what happens to the voltage across an LED and the current through that LED when the LED is shorted. This explanation should also become part of your own mental model of how circuits work. Edit View Insert Format Tools Table 12pt v Paragraph v B I U A & v TV V Ev Ev To V Vx H p O words >