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Please help me solve for B apparently I got it wrong Do Homework - Chapter 9.2 - Google Chrome - X mathxl.com/Student/PlayerHomework.aspx?homeworkld=614017216&questionld=3&flushed=true&cld=6738062¢erwin=yes MATH M15 -

Please help me solve for B apparently I got it wrong

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Do Homework - Chapter 9.2 - Google Chrome - X mathxl.com/Student/PlayerHomework.aspx?homeworkld=614017216&questionld=3&flushed=true&cld=6738062¢erwin=yes MATH M15 - Introductory Statistics - 73132 Matthew Prince | 12/07/21 8:35 PM Homework: Chapter 9.2 Question 4, 9.2.7-T HW Score: 36.36%, 4 of 11 points Part 5 of 6 * Points: 0 of 2 Save A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Proctored Nonproctored H2 n 35 31 x 74.25 86.73 S 10.06 19.05 O A. HO: My # H2 OB. HO H1 = H2 H1: Hy H2 H1HIGH2 The test statistic, t, is - 3.27 . (Round to two decimal places as needed.) The P-value is 0.001 . (Round to three decimal places as needed.) State the conclusion for the test A. Reject Ho- There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. O B. Reject Ho. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests O C. Fail to reject Ho. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. O D. Fail to reject Ho. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. 2.68

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