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Solution : The information given in the problemet as fallowy . Radius of the circula path whet larged is petelog R = 151- 6 linear velocitya Target VT = 31.3 m/s Positional large 310 Now, Draw is 287 meter outside the circled an angle 231" let the required velocityof Doone will be ve Now, let Doone travel at constant velocity Up and intercept the target at pointB on UT Tooget the circular . FRA we aregiven Distance from 2310 310 point c to B = 287 m R at CB = Sp = Distance traveled by Doone from CtoB B ' R = 151. 6m 2 Now, we know that C Are lengh = Radius x (angle difference ) Drome Distance travelled by Target for point A to B Sip = Radius x ( angle dieffect ) = ( 15 1 6 0 ) x ( 23 1 - 31 ) X -2 180Here we have converted angle form Degree to Patchxi. S = 151.6 X 200 X7 180 5 151. 6 X (1 . 117) we are given VJ = 313 mlg. Now, If both the target and the drone will begin at the Same time , then they will reach at point B after equal time inferval to = to trz time taken by tagged to reach for point A to B Ap = time taken by Doone to reach from point ctoB = *T SD = Vp ( 287 m ) = 151 .6 X 1.117 VD 31. 3 m/8 287 X 31 . 3 = VD I S I . 6 X 1 . 1 1 X 71 89 83. 1 = Up 168.27 X 3.19 Vp = 89 83. 1 = 17. 0016 m/8 52 8. 3678 VD = 17:00 m/3Diagram: Q: =-413 pC EA.8 di= 181 cm BA= 39" QA= +221 HC da= 274 cm Given: QA= +221 HC Q:= -413 pic da= 274 cm da= 181 cm BA= 39" Proton charge = +1.602 x 10-19 = tan-1 713,221.4524 Proton mass = 1.67 x 10-27 Note: 1.145,392.311 The lines of force in a Electric Field emanates from the positive charge and go to the negative charge like changes repel each other and unlike charges attract each other Solutions: A. EA= ? Formula: Convert cm to meters: KOA EA= - 274 cm X 100 1 = 2.74 m 8.99 x 10 (221 x10 ) 2.74 = 264,637.1677 N/C B. EB= ? Convert cm to meters: Formula: Es= 181 cm X 100 = 1.81 m 8.99 x10 (413 x 10-) 1.81" # 1,133,320.106 N/CCase: A target is patrolling at a circular path with a radius of 151.6 meters. The target is observed to have a linear velocity of 31.3 m/s. The target is situated at initial location of 310 in the circular path. A drone will be launched to intercept the moving target which is found 287 meters outside the circular at an angle of 2310. Question: Constant velocity that the drone needs to maintain in a straight line in order to intercept the moving target if both the target and the drone will begin moving at the same time = m/s (2 decimal places) Note: You need to get the correct answer in order to unlock the submission form where the document containing the analysis and diagram will be attached.C. EA, D= ? Formulas: Conversion of angle from radian to degree: Ex= EAX + Esx = EAX + Ex COs 0 360 A = 0.68067840827779 x = 264,637.1677 + 1,133,320.106 cos (398) = 390 = 1,145,392.311 Ey = EAY + Env = 0 + Ear sin 0 = 1,133,320.106 sin (399) = 713,221.4524 = 1,145,392.311 - + 713,221.4524- = 1,349,299.221 N/C D. BC =? Formula: 8 = tan 1 _ =tan-1 713,221,4524 1 145.392.311 = 31.91000499 E. A= ? Formulas: F= ma F= EQ 2 ma= EA BQ A= 1,349,299.221 (1.602 x 10-19) 1.67 x10-37 = 1.2943577 x 1014