Please help me with my stats assignment!For #6 the options for A)H0 and Ha: , 1- 2,p,p1-p2Then the options are ?, =, Then the options are 0.072, or 0.0943Then for #6 d) The options are reject, or fail to reject#6 e)The options are provides, or does not provide For #7 the options for A)H0 and Ha: , 1- 2,p,p1-p2Then the options are ?, =, Then the options are 0.0218, or 0.0552Then for #7 d) The options are reject, or fail to reject#7 e)The options are provides, or does not provide For #8 the options for A)H0 and Ha: , 1- 2,p,p1-p2Then the options are ?, =, Then the options are 0.076, or 0.065Then for #8 d) The options are reject, or fail to reject#8 e)The options are provides, or does not provide
A newspaper conducted a statewide survey concerning a proposal to raise A local the-star restaurant asks its patrons to fill out a quick satisfaction A computer manufacturing company claims that only 7:2%% of their survey (is the patron satisfied or not] after their meal, and the restaurant computers are returned. Kelly thinks that the company is misrepresenting taxes in order to prevent budget cuts to education. The newspaper took a claims that their satisfaction rating is 83%%. Jennie, a food critic, would the true proportion of computers that are returned, and that the true random sample (assume it is an SRS) of 400 registered voters and found to test this. She takes a sample of 180 patrons, and gets a 79.3%% sample proportion is higher than they claim. She wants to test this using a = 0.1. that 132 would vote to raise taxes. Let p represent the proportion of satisfaction rating. Kelly takes a sample of 265 computers and observes that 25 are returned. Assume a normal sampling distribution. registered voters in the state that would vote to raise taxes. (Round your (a] Create a 90%% confidence interval for the restaurant's true satisfaction answers to 4 decimal places, if needed.) rating. (Provide answers in decimal form, not percentage. Thus, 79 3% () What are the null and alternative hypotheses? becomes 0.793. Round your answers to four decimal places, If needed. Ho: P * * 0.072 # (a) The standard error for the sample proportion is HAi P = * 0.072 6 2 (b) The margin of error for a 96% confidence interval for p is (b) Based on this confidence interval, should Jennie reject the null (b) What is the test statistic? (Round your answer to 2 decimal places, If hypothesis that the satisfaction rating is 83% needed. O Since the interval does not contain 83%%, Jennie should reject the null hypothesis at a = 0.1. A researcher would like to estimate the proportion of home-based Since the interval contains 83%%, Jennie should not reject the null [c) Using the statistical table, what is the p-value? (Round your answer to 4 hypothesis at a = 0.1 decimal places, if needed.) businesses owned by women. What is the minimum sample size needed to be 99% confident with a 2 3% margin of error? (Round your answer to the D Since the interval does not contain 83%%, Jennie should not reject the null hypothesis at a = 0.1. appropriate integer.) (d) Based on the p-value, Kelly shoul v reject he null 3 Since the interval contains 83%%, Jennie should reject the null hypothesis at a = 0.1. hypothesis. fail to reject Answer: n = (el This data provides * sufficient evidence to conclude that the true proportion of computers is higher than claimed. A poll of 204 home sellers found that 25.1%% were trying to sell their home without a real estate agent. The margin of error for this poll was 5.0%%. Find In April of 2011, the unemployment rate in Canada was reported to be 7.6%. the approximate confidence level used by the pollsters. 4 A company creates wooden furniture to be sold at various retailers. This Suppose that Statistics Canada claims that the current unemployment rate Answer: 2 (Enter one of the following: 80, 90, 95, 98, 99) company claims that only 2.18%% of their furniture are defective in some is lower than that of April 2011. Suppose a test was conducted on current manner. Monica would like to test this claim to see if the actual percentage unemployment and a random sample size of 1200 found an unemployment of furniture that is defective is different than the company claims, using a = rate at 6.5%. Test an appropriate hypothesis and state your conclusion. Use 0.025. She takes a sample of 1340 pieces of furniture, and observes that 74 a significance level of 2.0%. of these furniture pieces are defective. Assume a normal sampling A 98% confidence intervals for the proportion of first-year statistics distribution. (a) What are the null and alternative hypotheses? students with brown hair is given to be (0.26, 0.41). (a) What are the null and alternative hypotheses? Ho: P =* 0.076 + 8 (a) What is the sample proportion of students with brown hair? Ho: P
