Please help me with the mean of the sampling distribution

Google Chrome ent/PlayerHomework.aspx?homeworkld=627127908&questionld=13&flushed=false&cld=6945111¢erwin=yes X her 2022 Rita Yousif 08/09/22 6:35 PM ework 5 Question 13, 5.4.13 HW Score: 95.83%, 19.17 of 20 points Part 4 of 6 Points: 0.17 of 1 Save K For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 94, 98, 97. Use a sample size of 3. The mean of the population is 96.33 (Round to two decimal places as needed.) The standard deviation of the population is 1.70 (Round to two decimal places as needed.) Identify all samples of size 3 with the correct accompanying means below. LY A. 94,97,94 x = 95 B. 98,97,97 x= 97:33 [Y C. 97,98,98 x = 97.67 LY D. 97,98,97 x=97.33 LY E. 94,97,98 x = 96.33 F. 94,98,97 x = 96.33 LY G. 97,97,97 x = 97 LY H. 94,94,94 x = 94 Y I. 94,94,97 x = 95 K. 94,94,98 x = 95.33 YL. 97,94,94 x = 95 LY J. 97,97,94 x = 96 YM. 98,97,98 x = 97.67 LYN. 97,94,97 x = 96 YO. 98,97,94 x = 96.33 LY Q. 98,98,94 x = 96.67 Y R. 94,98,94 x = 95.33 P. 98,94,94 x =95.33 LT. 98,94,98 x = 96.67 LY U. 97,94,98 x =96.33 LY S. 94,97,97 x = 96 YX. 97,97,98 x = 97.33 LYV. 98,98,97 x = 97.67 W. 98,94,97 x = 96.33 LY Z. 98,98,98 x = 98 97,98,94 x = 96.33 LYY. 94,98,98 x = 96.67 The mean of the sampling distribution is (Round to two decimal places as needed.) Clear all Check answer his View an example Get more help - 6:44 PM 24'C Partly sunny ~ 9 4) ENG 2022-08-09 e to search T450