Please help me with these questions. I don't need detailed explanations and calculations (just ABC) but if it is feasible, please post your draft! Please be careful, most of the time, experts give me many wrong answers (especially in Sta and Pro). Thanks so much, my pro!!!

Use the following information to solve problems 1-5 A random sample of 49 shoppers showed that they spend an average of $23.45 per visit at the store. The standard deviation of the population is $2.80. 1. The point estimate of the population mean is: a.23.45 b. 20 c. 25 2. With 90% confidence we can state that the actual population mean will fall between a. (22.79, 24.11) b. (22, 35) c. (21, 26) 3. The margin of error for the 90% confidence interval is: a. 1.32 b. 1.00 C. 0.66 4. With 99% confidence we can state that the actual population mean will fall between: a. (22, 24) b. (21, 25) c. (22.42, 24.48) 5. The margin of error for the 99% confidence interval is than that of the 90% confidence interval A. Wider B. Narrower C. Same as