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Please help me with this. Use known peak angle of 37.4 degrees You are considering the resistance of a piled foundation to vertical loads. The
Please help me with this.
Use known peak angle of 37.4 degrees
You are considering the resistance of a "piled foundation" to vertical loads. The piles are "sheet piles" and derive their resistance from the friction which acts on the vertical sides of the piles. In this problem, you will consider the piles to be "fully rough" so that the soil immediately next to the pile move with it and shearing happens between the soil grains (i.e. when we consider the friction, you will consider that the strength of the soil controls the resistance). The cross-section of the piles are shown below, and have dimensions x = 150 mm, y = 400 mm and t =10 mm. The thickness (t) is small enough that you may assume the dimensions of the inner face to be the same as the outer face. (i.e. x and y are the same on the both sides of the sheet pile). X Figure 1: Cross-section of the sheet pile. At the site of interest, your colleagues have indicated that the soil profile consists of loose sands (with a relative density of approximately 32 %) to a depth of 6.6 m below the ground surface, below which are dense sands (with a relative density of approximately 83 %). You may assume that it is the same type of sand in both layers, but at two different densities. At the estimated relative densities, it is expected that the earth pressure coefficient will be 0.5 in the loose layer, and 0.32 in the dense layer. The sands in this area are generally poorly graded, have a specific gravity of 2.73, a D50 of approximately 0.15mm, a Cu of approximately 3.5. The limiting void ratios are emin = 0.619 and emax = 1.098. The water table is located at approximately 2.4 m below the ground surface, and it is assumed that there is negligible capillary rise in these soils. The piles extend a total depth of 10.4 m below the ground surface. Part h) Estimate the total shear resistance pulling the pile out under peak conditions. Fok = kNStep by Step Solution
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