Please help! Provide answers and explanations if you can!!

Friction: Trig Formulas: Newton's Laws: Weight: sin 0 = opposite hypotenuse CF = 0 - a=0 Fg = mg Ofs S UsFN cos 0 = adjacent hypotenuse CF = ma Centripetal Acceleration: fk = HKFN tan 0 = opposite adjacent Fzon1 = - Flon2 Hooke's Law: ac = 02 / R Fs = -k(AT) 1. (8 pts) You push a box across a horizontal floor in a straight line. The frictional force is 23.0 N and you push the box with a positive force of 27.0 N. (a) What is the mass of the object if the coefficent of kinetic friction is 0.25? (b) What is the object's acceleration? (c) The box is now on a new surface where the coefficent of static friction is 0.40. With the same pushing force of 27.0 N, what is the new force of friction? 2. (4 pts) You pull a 65 kg box up a ramp at an angle of 15 with a rope that is parallel to the incline and with a tension equal to 450 N. If the coefficient of kinetic friction between the box and the ramp is equal to /k = 0.23, what is the box's acceleration up the ramp? Free Body Diagram ax T + 3. (6 pts) When you take your 1300 kg car out for a spin, you go around a corner of radius 75 m with a speed of 20 m/s. The coefficient of static friction between the car and the road is 0.88. (a) Assuming your car doesn't skid, what is the force exerted on it by static friction? (b) What is the max speed you can go without slipping? R