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The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 4? 34 30 46 33" 30 4? 36 25 49 33" 32 51 41 Sample mean 30 48 33" Sample variance 6.00 4.00 6.50 a. At the o: = 0.05 level of signicance. can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 815.0 8 Sum of Squares, Error 8 Mean Squares, Treatment 8 Mean Squares, Error 6 Calculate the value of the test statistic (to 2 decimals). t3 Mean Squares, Error '9 Calculate the value of the test statistic (to 2 decimals}. 8 The p-value is | less than 9.01 v | M What is vour conclusion? I Conclude that not all treatment means are equal V I M b. Calculate the value of Fisher's LSD {to 2 decimals]. 8 Use Fisher's LSD procedure to test whether there is a signicant difference between the means for treatments A and B, treatments A. and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion 5153 9 |W| *3 |:I