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The exponential model A: 968.8 E 0'01 1' describes the population, A, of a countryr in millions, t years after 2003. Use the model to determine the population of the country in 2003. The population of the country in 2003 was million. Complete the table shown to the right for the half-life of a certain radioactive Half-Life Decay Rate, k substance. 16.2 days . . .. . K= (Round to six decimal places as needed.)The halflife ofa certain tranquilizer in the bloodstream is 50 hours. How long will it take for the drug to decay to 85% of the original dosage? Use the exponential decay.' model. A = A0 e H. to solve. hours (Round to one decimal place as needed.) The exponential models describe the population of the indicated country,A, in Country 1: A : 239 8 0.021! millions. t years after 2006. Which country has the greatest growth rate? By what _ _ 0.0041 percentage is the population of that country increasing each year? Country 2' A '132'4 B D U12t Country 3: A =1039] 2 ' Country 4; A 21429 e Upon Country :I has the greatest growth rate. The exponential model A: 42? e 0'03 descn'bes the population, A, of a country in millions, t years after 2003. Use the model to determine when the population of the country will be 7'48 million. The population of the country will be 748 million in (Round to the nearest year as needed.) 2004 Projected 2029 Population Projected Growth Population(millions} {millions} Rate, It Complete the table shown to the right for the population growth model for a certain country. 95.2 0.0081 The projected 2029 population is million, (Round to one decimal place as needed.) Complete the table shown to the right for the population growth model for a certain country. 2005 Population Projected 2034 Population Projected Growth (millions) {millions} Rate, k 31.8 13.6 [(2 (Round to four decimal places as needed.) An artifact originally had 16 grams of carbon14 present. The decay model A =16 e _ 000012\" describes the amount of carbon14 present after t years. Use the model to determine how many grams of carbon14 will be present in 8603 years. The amount of carbon14 present in 8603 years will be approximately grams. (Round t0 the nearest whole number.) The half-life of the radioactive element unobtanium-31 is 5 seconds. If 176 grams of unobtanium-31 are initially present, how many grams are present after 5 seconds? 10 seconds? 15 seconds? 20 seconds? 25 seconds? The amount left after 5 seconds is grams.Prehistoric cave paintings were discovered in a cave in France. The paint contained 36% of the original carbon14. Use the exponential decay model for carbon14, A: A0 e $30012\Complete the table shown to the right for the halflife of a cenain radioactive Half-Life Decay Rate, It substance. 4.3% per year = 0.043 The halflife is years. (Round to one decimal place as needed )