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Please help with steps and explanation. Please and thank you. In Figure (a), a beam of light in material 1 is incident on a boundary

Please help with steps and explanation. Please and thank you.

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In Figure (a), a beam of light in material 1 is incident on a boundary at an angle of 01 = 30. The extent of refraction of the light into material 2 depends, in part, on the index of refraction n2 of material 2. Figure (b) gives the angle of refraction 02 versus no for a range of possible n2 values. The vertical axis scale is set by 020 = 140 and 02b = 460. (a) What is the index of refraction of material 1? (b) If the incident angle is changed to 840 and material 2 has n2 = 3.2, then what is angle 02? 0 95 30% 1.3 3 1.5 1.7 1.9. (a) (b) (a) Number Units (b) Number i Units

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