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Please help with this questions: Note: For Question 5, the choices for a) is: 1. for all / there exists 2. for all / there
Please help with this questions:
Note: For Question 5, the choices for a) is: 1. for all / there exists 2. for all / there exists 3. does not belong to / belongs to
for b) 1. for all / there exists 2. for all / there exists 3. does not equal to / equals to
D Question 6 1 pts To prove the claim: " for any integer a if 3a+1 is even, then a is odd" by contrapositive we need to show that O if 3a+1 is odd, then a is odd. if a is odd, then 3a+1 is even. O if 3a+1 is odd, then a is even. O if 3a+1 is even, then a is even. O if a is even, then 3a+1 is odd. D Question 7 1 pts To prove the claim: " for any integer a if 3a+1 is even, then a is odd" by contradiction we need to show that O for any integer a we have that 3a+1 is odd and a is even. O there is an integer a such that 3a+1 is even and a is even. O there is an integer a such that 3a+1 is even and a is odd. O for any integer a we have that 3a+1 is even and a is even. O for any integer a we have that 3a+1 is even and a is odd.D Question 5 1 pts Let S be a subset of R. From the drop-down menu choose quantifiers, connectives and logic symbols to form correct negations of the given statements P: (a) P =" S is closed under addition". Then -P is [ Select ] va ES)( [Select ] " b ES ) [atb [ Select ] v S] . (b) P =" There is a multiplicative identity in S". Then -P is [ Select ] V X ES)( [ Select ] vy ES) [xy [ Select ] v y ]Step by Step Solution
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