PLEASE MAKE SURE FORMATTING IS UNDERSTANDING AND READABLE! I have arranged the questions in the order they should be in, please only provide answer with section, question number and part (ex. 1a, 1b, 2a, 2b, etc.). Only part that needs to be answered is the incorrect ones.

Section 9.4

1.

Consider the following hypothesis test: H0: ,u g 12 Ha: ,u > 12 A sample of 25 provided a sample mean E = 14 and a sample standard deviation 5 = 4.32. 3. Compute the value of the test statistic (to 2 decimals). 0 b. Use the 13 distribution table (Table 2 in Appendix B) to compute a range for the pvalue. The pvalue is between 0.01 and 0.025 v M c. At a = 0.05, what is your conclusion? Reject null hypothesis V M. d. What is the rejection rule using the critical value? (Use a = 0.05.) Reject Ho ift e w the ermeei value of 0 (to 3 decimals). Can you conclude that the population mean is greater than 12? k~9 Consider the following hypothesis test: H0: [1 = 18 Ha: p, 75 18 A sample of 48 provided a sample mean 5 = 17 and a sample standard deviation 5 = 4.5. Enter negative values as negative numbers. 3. Compute the value of the test statistic (to three decimal places). 0 b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the pvalue (to two decimal places). pvalue is between 0 and 0. c. At a = 0.05, what is your conclusion? p-Value is greater than 0.05, do not reject v 9 Ho. d. What is the rejection rule using the critical value? Reject H0 if t is less than or equal to -2.012 v M or t is greater than or equal to 2.012 v 9. What is your conclusion (to three decimal places)? 9Wa- TABLE 2 DISTRIBUTION Area or probability Entries in the table give : values for an area or probability in the upper tail of the distribution. For example, with 10 degrees of freedom and a 05 arca in the upper tail. fors = 1.812. Area in Upper Tail Degrees 20 10 05 025 .01 .005 of Freedom 61.821 63.656 1.376 3.078 6.314 12.706 2.920 4.303 6.965 9.925 1.061 1.886 978 1.638 2.353 3.182 4.541 5.841 1533 3,747 4.604 941 2.132 2.776 2015 4.032 920 1.476 2.571 3.365 906 1.440 1.943 2.447 3,143 3.707 .896 1.415 1.895 .36 2.998 3.499 1.397 1.860 2.306 2.896 3.355 .889 883 1.383 1.833 2.262 2.821 3.250 1.372 1.812 2.228 2.764 3.169 879 876 1.363 1.796 2.201 2.718 3.106 .873 1.356 1.782 2.179 2.681 3.055 3.012 870 1.350 1.771 2.160 2.650 868 1.761 2 145 2.624 2.977 1.345 866 1.341 1.753 2.131 2.602 2.947 865 1.337 1.746 2.120 2.583 2.921 1.333 1.740 2.110 2.567 2.898 863 862 1.330 1.734 2.101 2552 2.878 1.328 1.729 2093 2.539 2.861 361 860 1.325 1.725 2.086 2.528 2.845 .859 1.323 1.721 2.080 2518 2.831 .858 1.321 1.717 2.074 2.508 2.819 .858 1.319 1.714 2.069 2.500 2.807 857 1 318 206 2.492 2.797 .856 1.316 1,708 2.060 2.485 2.787 .856 1.315 1.706 2.056 2.479 2.779 .855 1.314 1.705 2.052 2.473 2.771 855 1.313 1.701 2.048 2467 2,763 .854 1.31 1.699 2.045 2.462 2.756 2.457 2.750 854 1.310 1.697 2.042 853 1.309 1.696 2040 2.453 2.744 853 1.309 1.694 2.037 2 449 2.738 .853 1.308 1.692 2.035 2.445 2.733 852 1.307 1.691 2032 2.441 2,728 Area In Upper Tall Degrees of Freedom .20 01 -005 10 2.724 35 852 1.30 1.690 2.030 2.438 .852 1.306 1.688 2.028 2.434 2.719 .851 1.305 1.687 2.026 2.431 2.715 .851 1.304 .686 2.024 2.429 2.712 851 1.304 685 2.023 2.426 2.708 851 1.303 1.684 2.021 2.423 2.70 .850 .303 683 2.020 2.421 2.701 .850 1.302 682 2.018 2.418 2.698 .850 1.302 681 2.017 2.416 2.695 .850 1301 1.680 2.015 2.414 2.692 .850 1.301 1.679 2.014 2.412 2.690 850 1.300 1.679 2.013 2.410 2.687 849 1.300 .678 2.012 2.408 2.685 849 1.299 .677 2.011 2.407 2.682 849 1299 637 2010 2.405 2.680 849 1.299 1.616 2.009 2.40 2.678 .849 1.298 1.675 2.008 2.402 2.676 849 1.298 1.675 2.007 2.400 2.674 848 1.298 1674 2.006 2.399 2.672 84 1297 1.674 2.005 2.397 2.670 848 1.297 1.673 2.004 2.396 2.668 848 1.297 1.673 2.006 2.395 2.667 848 1.297 1.672 2.002 2.304 2.665 848 1.296 1.672 2.002 2.392 2.663 848 1.296 1.671 2.001 2.391 2.662 2.390 2.660 848 1.296 1.671 2.000 848 1.296 1670 2.000 2.389 2.659 847 1.295 1.670 1.999 2.388 2.657 847 1.295 .669 1.998 2.387 2.656 847 1.295 1.669 1.998 2.386 2.655 847 1.295 1.669 1.997 2.385 2.65 .847 1.295 .668 1.997 2.384 2.652 .847 1.294 .668 1.996 2.383 2.651 .847 1.294 668 1.995 2.382 2.650 847 1.294 .667 1.905 2.382 2.649 847 1.294 1.667 1.994 2.381 2.648 847 1.294 66 1.904 2.380 2.647 847 1.293 666 1.993 2.379 2.646 847 1.293 -666 1.993 2.379 2.645 847 1.293 1.666 1.993 2.378 2.644 1.293 2.643 846 1.665 1.992 2.377 1.293 1.665 1.992 2.376 2.642 846 1.293 1.665 1.991 2.376 2.641 1.292 1.665 1.991 2.375 2.640 1.292 1664 1.990 2.374 2.639 846 Area in Upper Tail Degrees 20 10 05 025 .01 005 of Freedom 1.292 1.664 1.990 2.639 .846 2.374 2.638 846 1.292 1.664 1.990 2.373 846 1.292 1.664 1.989 2.373 2.637 846 1.292 1.663 1.989 2.372 2.636 846 1.292 1.663 1.9:85 2.372 2.636 846 1.292 1.663 1.988 2.371 2.635 846 1.291 1.66 1.988 2.370 2.634 .846 1.291 1.663 2.370 2.634 .846 1.291 1.662 1.987 2.369 2.633 1.291 2.369 846 2.632 1.291 1.662 1.987 2.368 2.632 846 846 1.291 1.662 1986 2.368 2.631 846 1.291 1.662 2.368 2.630 846 1.291 1,661 2.36 2.630 :838985 28328 9838 845 1.291 1.661 986 2.367 2.629 845 1.291 1.661 1.985 2.366 2.629 845 1.290 1.661 1985 2.366 2.628 .845 1.290 1.661 .985 2.365 2.627 845 1.290 1,661 1.984 2.36 2.627 845 1.660 1.984 2 364 2.626 1.290 .845 1.290 1.660 1.984 2.364 2.626 842 1.282 1.645 1.960 2.326 2.576Consider the following hypothesis test: H0 : ,u = 140 Ha : ,u 7E 140 A sample of 60 is used. Identify the pvalue and state your conclusion for each of the following sample results. Use 0: = 0.05. Round the value of the test statistic to three decimal places. If required enter negative values as negative numbers. a. E = 143 and s = 12.5 t-value 0 p-value between 0.05 and 0.10 v @ conclusion do not reject v 9 H0 b. E = 136 and s = 10.5 t-value 0 p-value lower than 0.01 v @ c.=145ands=11 t-value 0 p-value lower than 0.01 v w According to the Vivino website, the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New Englandbased lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 56 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively. 3. Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. Ho: [A greater than or equal to 32.43 v M H u w b. Using the sample from the 56 bottles, what is the pvalue? The p-value is between 0.05 and 0.10 v M. c. At a = 0.05, what is your conclusion? M the null hypothesis. We 9 conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. d. Repeat the preceding hypothesis test using the critical value approach. 75 is K0 the critical value of 0 (to 3 decimals), Q0 the null hypothesis. A shareholders' group, in lodging a protest, claimed that the mean tenure for a chief executive officer (CEO) was at least nine years. A survey of companies reported in The Wall Street Journal found a sample mean tenure of a = 8.09 years for CEOs with a standard deviation of s = 7.4 years. a. Formulate hypotheses that can be used to challenge the validity of the claim made by the shareholders' group. Ho : H 2 Ha : M