Please need an answer asap

Use the Laplace transform to solve the following initial value problem: y' - 23/ + 26y=0 y(0) = 0, y (0) =5 a. Using Y for the Laplace transform of y(t), i.e., Y = [ty(t) }, find the equation you get by taking the Laplace transform of the differential equation =0 b. Now solve for Y(s) = c. By completing the square in the denominator and inverting the transform, find y(t) =