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1. value: 3.03 points MC Qu. 27 A marketing firm is studying consumer prefer... A marketing firm is studying consumer preferences for winter fashions in four different months. From a population of women, 18-21 years of age, a random sample of 436 women was selected in January. Another random sample of 436 women was selected in March. Another random sample of 436 women was selected in June. Another random sample of 436 women was selected in September. The sample size was 436. The sample size was 1,744. The sample size was 1. The sample size was 4. 2. value: 3.03 points MC Qu. 23 Using a 5% level of significance and a sampl... Using a 5% level of significance and a sample size of 26, what is the critical value for a one-tailed hypothesis test? 1.708 1.347 2.060 1.485 3. value: 3.03 points Exercise 8-14 -2-2 http:/ /ezto.mhedu Given below are the last four digits of 18 random phone numbers of your local population. 2,707 9,595 3,822 1,254 3,184 9,709 8,560 6,471 5,789 3,275 4,807 4,896 3,865 3,484 6,741 1,333 5,792 1,254 Fill in the frequency table of the final digit of 18 randomly selected phone numbers. Digit Frequency 0 1 2 3 4 5 6 7 8 9 Using the sample mean of the final four digits (9704 would lead to a mean of 5), compute the mean of the sample means. (Round your answer to 2 decimal places.) Mean of the sample means 4. value: 3.03 points MC Qu. 58 A group of statistics students decided to co... A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spend studying per week. Based on a simple random sample, they surveyed 148 students. The statistics showed that students studied an average of 20 hours per week with a standard deviation of 14 hours. What is the standard error of the mean? 1.15 14 1 0.7 5. value: 3.03 points MC Qu. 67 The mean gross annual incomes of certified w... The mean gross annual incomes of certified welders are normally distributed with the mean of $25,588 and a standard deviation of $2,559. The ship building association wishes to find out whether their welders earn more or less than $25,588 annually. The alternate hypothesis is that the mean is not $25,588. Which of the following is the alternate hypothesis? H1: $25,588 H1: 27 (a) Is this a one- or two-tailed test? "Two-tailed"-the alternate hypothesis is different from direction. "One-tailed"-the alternate hypothesis is greater than direction. (b) What is the decision rule? (Round your answer to 2 decimal places.) H0,when z > (Click to select) (c) What is the value of the test statistic? (Round your answer to 2 decimal places.) Value of the test statistic (d) What is your decision regarding H0? Do not reject Reject There is evidence to conclude that the population mean is greater than 27. (Click to select) (e) What is the p-value? (Round your answer to 4 decimal places.) p-value 11. value: 3.03 points MC Qu. 60 A survey of... A survey of 21 grocery stores revealed that the average price of a gallon of milk was $3.11 with a standard error of $0.10. What is the 95% confidence interval to estimate the true cost of a gallon of milk? $3.08 to $3.15 $3.07 to $3.07 $2.90 to $3.32 $3.14 to $3.15 12. value: 3.03 points MC Qu. 42 If... If 31 out of 61 students sampled live in a college dormitory, what is the estimated proportion of students at the University living in a dormitory? 0.61 0.51 0.31 0.82 13. value: 3.03 points MC Qu. 68 A sample of... A sample of 23 is selected from a known population of 99 elements. What is the finite population correction factor? 0.88 Cannot be determined 86 9.6 14. value: 3.03 points MC Qu. 59 A group of statistics students decided to co... A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spend studying per week. Based on a simple random sample, they surveyed 147 students. The statistics showed that students studied an average of 20 hours per week with a standard deviation of 10 hours. What is the probability that a sample mean would exceed 20 hours per week? 0.5 Cannot be calculated based on the given information. 1.5 1 15. value: 3.03 points MC Qu. 26 A random sample of... A random sample of 29 items is selected from a population. To determine the appropriate critical t-value what number of degrees of freedom should be used? 35 42 31 28 16. value: 3.03 points MC Qu. 28 What are the two critical values for a two-t... What are the two critical values for a two-tailed test with a 0.03 level of significance when n is large and the population standard deviation is known? Above 1.00 and below -1.00 Above 2.17 and below -2.17 Above 2.30 and below -2.30 Above 0.74 and below -0.74 17. value: 3.04 points Exercise 9-42 -2-2 http:/ /ezto.mhedu As a condition of employment, Fashion Industries applicants must pass a drug test. Of the last 240 applicants, 23 failed the test. (1) Develop a 98% confidence interval for the proportion of applicants that fail the test. (Round your answers to 3 decimal places.) For the applicants, the confidence interval is between and . (2) Would it be reasonable to conclude that more than 5% of the applicants are now failing the test? No Yes 18. value: 3.03 points MC Qu. 59 It is claimed that in a bushel of peaches le... It is claimed that in a bushel of peaches less than ten percent are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the null hypothesis? H0: 0.10 H0: 0.10 H0: 0.10 H0: 13.2 28. value: 3.03 points Exercise 8-36 -2-2 http:/ /ezto.mhedu A recent study by the Greater Los Angeles Taxi Drivers Association showed that the mean fare charged for service from Hermosa Beach to Los Angeles International Airport is $25 and the standard deviation is $3.30. We select a sample of 19 fares. What is the likelihood that the sample mean is between $24 and $26? Assume the population of fares is normally distributed. (Round z value to 2 decimal places and final answer to 4 decimal places.) Probability 29. value: 3.03 points MC Qu. 21 Mileage tests were conducted on a randomly s... Mileage tests were conducted on a randomly selected sample of 100 newly developed automobile tires. The results showed that the average tread life was 54,430 miles with a standard deviation of 3,505 miles. What is the best estimate of the average tread life in miles for the entire population of these tires? (54,430/100) 54,430 (3,505/100) 3,505 30. value: 3.03 points Exercise 10-3 -2-2 http:/ /ezto.mhedu A sample of 37 observations is selected from a normal population. The sample mean is 25, and the population standard deviation is 5. Conduct the following test of hypothesis using the .05 significance level. H0 : 24 H1 : > 24 (a) Is this a one- or two-tailed test? "One-tailed"-the alternate hypothesis is greater than direction. "Two-tailed"-the alternate hypothesis is different from direction. (b) What is the decision rule? (Round your answer to 2 decimal places.) H0,when z > (Click to select) (c) What is the value of the test statistic? (Round your answer to 2 decimal places.) Value of the test statistic (d) What is your decision regarding H0? Reject Do not reject There is evidence to conclude that the population mean is greater than 24. (Click to select) (e) What is the p-value? (Round your answer to 4 decimal places.) p-value 31. value: 3.03 points Exercise 9-3 -2-2 http:/ /ezto.mhedu A sample of 255 observations is selected from a normal population for which the population standard deviation is known to be 26. The sample mean is 16. (a) Determine the standard error of the mean. (Round your answer to 3 decimal places.) Standard error of the mean (c) Determine the 98% confidence interval for the population mean. (Round your answers to 3 decimal places.) Confidence interval and rev: 03_25_2013_QC_28306 32. value: 3.03 points MC Qu. 57 A student wanted to construct... A student wanted to construct a 95% confidence interval for the average age of students in her statistics class. She randomly selected 8 students. Their average age was 21.2 years with a standard deviation of 1.6 years. What is the best point estimate for the population mean? 21.2 years 3.2 years 9 years 2.2 years