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How much faster is a machine compared with a perfect cache that never 3 points misses? You can assume: Frequency of data transfer instructions are 40% of all instructions. Instruction cache miss rate 6%, data cache miss rate 2% and miss penalty always 20 cycles. CPI of 2 without memory stalls. That machine is faster by a factor of 2.36 as compared with a perfect cache That machine is slower by a factor of 0.42 as compared with a perfect cache. Perfect machine is better by a factor of 0.42 compared to that machine Perfect machine is worse by a factor of 2.36 compared to that machine 0 none of the given options Will there be any data hazards into the codes below. If yes, then how many 2 paints cycles need to be stalled with the forwarding? Assume no control and structural hazards. Without workouts using multiple clock cycle diagram. you will not get full marks. 7w $t2, 4($to) add $t3, $t1, $t2 SW $t3, 12 ($t0) 2 stalls with forwarding 2 stalls without forwarding 1 stall without forwarding no stalls 1 stall with forwarding