Please, please, please read my instructions carefully. I have already posted this question once on Chegg, and one expert has already answered the question. His explanation was a little big; however, I did understand some of it.

My answer is "paper handwriting." Please confirm if the way I did it is the correct answer. Also, he did not answer part B, where it says, "Choose the correct time-phased product structure below." Please provide an answer for that as well. I don't know if that is A) B) C) 0r D). Thank you.

You need to schedule 10 units of product Alpha for delivery in 6 weeks. Three units of D and 2 units of F are required for each Alpha. The lead time for Alpha is 1 week. Lead time for D is 1 week, and lead time for F is 2 weeks. a) Complete the product structure. b) Choose the correct time-phased product structure below. A. B. C. D. c) Prepare a gross requirements plan for Alpha (enter your rosponses as whole numbers). b) Choose the correct time-phased product structure below. A. B. c. c) Prepare a gross requirements plan for Alpha (enter your responses as whole numbers). You need to schedule 10 units of product Alpha for delivery in 6 weeks. Three units of D and 2 units of F are required each Alpha. The lead time for Alpha is 1 week. Lead time for D is 1 week, and lead time for F is 2 weeks. a) Complete the product structure. c) Prepare a gross requirements plan for Alpha (enter your responses as whole numbers). You need to schedule 10 units of product Alpha for delivery in 6 weeks. Three units of D and 2 units of F are requin each Alpha. The lead time for Alpha is 1 week. Lead time for D is 1 week, and lead time for F is 2 weeks. c) Propare a gross requirements plan for Alpha (onter your responses as whole numbers). ed to schedule 10 units of product Alpha for delivery in 6 weeks. Three units of D and 2 units of F are required Alpha. The lead time for Alpha is 1 week. Lead time for D is 1 week, and lead time for F is 2 weeks. mplete the product structure. noose the correct time-phased product structure below. B. B. C. Alpha F(3) F(2) Time in weeks D. D. Prepare a gross requirements plan for Alpha (enter your responses as whole numbers). Require Date order felease required Date order release require Date - rder releage Explanation: Product Structure - Top: (1) Subassembly A - Left: (2) Component B - Right: (3) Component C Explanation Subassembly A is composed of Component B and Component C. In order to produce one unit of Subassembly A, one unit of Component B and one unit of Component C are required. B. If 100 units of Subassembly A are required, how many units of Component B and Component C are needed? - Component B : 100 units - Component C: 100 units Explanation For every unit of Subassembly, A, one unit of Component B and one unit of Component C are needed. Therefore, to produce 100 units of Subassembly A, 100 units of Component B and 100 units of Component C are needed. C. If there are 20 units of Component B and 30 units of Component C on hand, how many additional units of each component are needed to produce 100 units of Subassembly A? C. If there are 20 units of Component B and 30 units of Component C on hand, how many additional units of each component are needed to produce 100 units of Subassembly A? - Component B : 80 units - Component C : 70 units Explanation To produce 100 units of Subassembly A, 100 units of Component B and 100 units of Component C are needed. However, there are already 20 units of C mponent B and 30 units of Component C on hand. Therefore, the following additional units are needed: - Component B : 100 units -20 units =80 units - Component C:100 units -30 units =70 units Step 2/4 Explanation: Product Structure - Top: Alpha - Left: D (3 units) - Right: F ( 2 units) Product Structure - Top: Alpha - Left: D (3 units) - Right: F (2 units) Time-Phased Product Structure Explanation The time-phased product structure shows the quantity of each component required at each week in order to produce the 10 units of Alpha that are due in week 6. - In week 5,30 units of D and 20 units of F are required to start production of the 10 units of Alpha. - The lead time for Alpha is 1 week, so the 10 units of Alpha will be completed in week 6 . Explanation The gross requirements plan shows the cumulative quantity of Alpha that is required each week. The gross requirements for each week is equal to the sum of the gross requirements for the previous week plus the net requirements for the current week. - In week 6 , the net requirements for Alpha is 10 units. - The gross requirements for week 6 is equal to the net requirements for week 6 , which is 10 units. Additional Notes - The lead time for a component is the time it takes to receive the component once it has been ordered. - The gross requirements for a component is the total quantity of the component that is required, including the quantity that is needed to meet demand and the quantity that is needed to maintain safety stock. - The net requirements for a component is the quantity of the component that is needed to meet demand. Explanation: Product Structure - Top: Alpha - Left: D (3 units) - Right: F ( 2 units) The time-phased product structure shows the quantity of each component required at each week in order to produce the 10 units of Alpha that are due in week 6. - In week 5, 30 units of D and 20 units of F are required to start production of the 10 units of Alpha. - The lead time for Alpha is 1 week, so the 10 units of Alpha will be completed in week 6 . - The lead time for D is 1 week, so the 30 units of D must be ordered in week 4 . - The lead time for F is 2 weeks, so the 20 units of F must be ordered in week 3. Explanation - The lead time for F is 2 weeks, so the 20 units of F must be ordered in week 3 . - The lead time for D is 1 week, so the 30 units of D must be ordered in week 4 . - The lead time for Alpha is 1 week, so the 10 units of Alpha will be completed in week 6 . Explanation - The lead time for F is 2 weeks, so the 20 units of F must be ordered in week 3. - The lead time for D is 1 week, so the 30 units of D must be ordered in week 4 . - The lead time for Alpha is 1 week, so the 10 units of Alpha will be completed in week 6 . The gross requirements plan shows the cumulative quantity of Alpha that is required each week. The gross requirements for each week are equal to the sum of the gross requirements for the previous week plus the net requirements for the current week. - In week 6 , the net requirement for Alpha is 10 units. - The gross requirements for week 6 are equal to the net requirements for week 6 , which is 10 units