Please respond in Python, thank you!

Q1. (5 points) Write a short program that simplifies the following code so that it does not use any break or continue statements, yet the logic is equivalent, and the code outputs the counter value of 126. counter =0 while True: if counter >=100: break elif counter %2=0: counter +=1 continue else: counter =2; continue print("counter:", counter) Q2. (5 points) Write a short program that will: - prompt the user for a number - print out whether the number is a perfect square and then end the program - prompt the user for another number if the input was not a perfect square Suggestion: Import the math module and use the sqrt() function to find the square root of a number. Example: import math math.sqrt(some_number) Sample Output: ============== Perfect Squares ============= Enter a number: 40 Not a perfect square. Enter a number: 60 Not a perfect square. Enter a number: 100 100 is a perfect square. Q3. (5 points) Write a short program that prompts the user for an integer and prints the integer, but if something other than an integer is input, the program keeps asking for an integer. Sample Output: Enter an integer: a Enter an integer: a Enter an integer: b Enter an integer: \% Enter an integer: 3 The integer is: 3 Deliverable