Answered step by step
Verified Expert Solution
Link Copied!

Question

...
1 Approved Answer

Please show and explain all work, there is a similar question to the one posted underneath. Thanks. supplementary notes from textbook: aae 34 MH2 Wave

Please show and explain all work, there is a similar question to the one posted underneath. Thanks.

image text in transcribed

supplementary notes from textbook:

image text in transcribed

image text in transcribed

image text in transcribed

aae 34 MH2 Wave a one 2 incident normall d:elechic ~ () to the the so b, Rt com plex voltagea ot dilberen Yeflection ad amomission pom 11-11 CONTINUOUS WAVE (CW) REFLECTIONS AND FEM As an extension of the Bouncing Pulses on the /4 transformer of Example 3-23 (Sec. 3-6), let us consider a case of a continuous wave incident on a thick dielectric slab. For the pulse we tracked only amplitude but for the continuous wave we must track both amplitude and phase. Example 11-6. Continuous wave on dielectric slab. A plane 200 MHz waye is incident normally on a dielectric slab of thickness 3.14 m and r-, 4, r-1,o-0. Calculate the VSWR in the three regions (a) to the left of the slab, (b) within the slab, (c) to the right of the slab and (d) draw the standing-wave pattern Solution. Taking the incident wave field strength equal to 1 Vm-1 and its phase atthe slab boundary as 0, we have from (4-7-9) and (4-7-12) that -j is reflected andis transmitted into the slab. At theright-hand boundary x0.222) is reflected and x-0.889) is transmitted. In crossing the slab the wave travels 2 x (3.14/1.5) -4.19 so at the right boundary the phase equals 0.19 x 360 68. The topof Fig. 11-12tracks theprogress ofthe wave as it bounces back-and-forth between the two boundaries. Adding the waves in air at the left of the left-hand bound- ary, we have 0.333 2180+ 0.296 2137 +0.033 22740.004 250 0.57 2162. Therefore, to the left of the boundary the VSWR- (1 0.57) 0.57)-3.65. Ans. (a). Distance d 3.14nm 333 L1800.6670 0.222L68 0.889L68 0.296L137 0.074L137 0.025L205 0.099 205 0.033 274 0.008 274 0.0031342 0.011342 0.004 50 0,00150 1.6 1.4 Di 08 0.6 0.4 VSWR1 VSWR 3.65 0.2 -1-0.5 0 0.5 1 .5 2 25 3 35 4 Distance, m 20-1892 Zo-377 2o- 3772 FIGURE 11-12 Continuous wave traveling through dielectric slab. Top Magnitude and phase of wave at multiple reflections. Center: Standing-wave pattern as drawn by FEM program of Slone and Lee. Bottom: Equivalent transmission line Proceeding in like manner in the dielectric the VSWR 2.00, Ans. (b), and to the right of the dielectric the VSWR-1.00, Ans. (c). Rodney Slone and Robert Lee of the Ohio State University have developed a fi nite element method (FEM) program whichproduces the standing-wave pattern shown in Fig. 11-12t Ans. (d). They explain the finite element method and apply it to several simple ca ses in cluding the one of Example 11-5. The program has several hundred lines and two sub- routines and can solve and plot the results for much more complex geometries. Thus, it can handle arbitrary values of and for multiple or continuously varying parameters

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access with AI-Powered Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Students also viewed these Accounting questions