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Area of a surface of revolution for y = f(z). Let f(a) be a nonnegative smooth function (smooth means continuously differentiable) over the interval Ja, b). Then, the area of the surface of revolution formed by revolving the graph of y = f() about the ex-axis is given by a 2n f( ) 1 + If' (x)|2 de . Part 1. Setup the integral that will give the area of the surface generated by revolving the curve f() _ e te over the interval (0, In 5] about the a-axis. In5 = O Part 2. Calculate the area of the surface of revolution described above. units squared. Note: enter your answer as an exact value without using decimals