Please show your work

A muon decays by the reaction ,u' >e' +v +179 (The muon decays into an electron and two neutrinos.) To simplify we will say A >B + vc + VD. mA = 200 MeV, m3 = 50 MeV. Before the decay, A is initially at rest. After the decay, vD goes le_ft with a momentum of ,9. VC goes Ligm with twice the momentum of VD (2p)- a) What is the direction and momentum of B in terms of p? b) Set up an equation to solve for ,0. Turn this into an equation that can be solved with the quadratic formula. The solution is p = 44.38 MeV/c. c) Find the energy and momentum of each of the 3 particles after the decay. Use a negative sign for negative values