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PLEASE SNAPSHOT FROM YOUR MATLAB SCRIPT TO SOLVE THIS PROBLEM. 1-D Strong Form For a given 1-D rod, the specified distributed body force is described

PLEASE SNAPSHOT FROM YOUR MATLAB SCRIPT TO SOLVE THIS PROBLEM.

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1-D Strong Form For a given 1-D rod, the specified distributed body force is described by: b(x) = b_0 astir (a) x/L. Determine u(x) if both sides of the rod are fixed Determine u(x) if the rod is fixed at u 0 and free at u = L Given the following: E = 20,000ksi, A = 10in^2, L 20in, b_0 = 10 lb/in, in plot your calculated displacement function for part b in MATLAB Calculate and plot the stress distribution for part b Tapered Rod For a tapered rod (A(x) is not constant), solving the strong form equation is harder, but still possible. For a 1-D rod with fixed end conditions, a constant distributed body force, b(x) = b_0 = 5 lb/in, and a cross-sectional area defined as A(z) = 5 +2x, the solution for the displaced shape looks like: u(x) = -1/E (1/4C_1 ln (2x+5)+C_2-5x/2) Determine u(x) if both sides of the rod are fixed (u(0) = 0, u(L) = 0) Given the following: E = 20,000ksi, A = 10in^2, L = 20in, b_0 = 5 lb/in, plot your calculated in displacement function in MATLAB Now approximate the solution using matrix/direct stiffness methods. Break the rod into several elements of varying areas and lump the distributed forces as point loads at the nodes. Plot your results on the same plot as Part b Comment on your solution? 1-D Strong Form For a given 1-D rod, the specified distributed body force is described by: b(x) = b_0 astir (a) x/L. Determine u(x) if both sides of the rod are fixed Determine u(x) if the rod is fixed at u 0 and free at u = L Given the following: E = 20,000ksi, A = 10in^2, L 20in, b_0 = 10 lb/in, in plot your calculated displacement function for part b in MATLAB Calculate and plot the stress distribution for part b Tapered Rod For a tapered rod (A(x) is not constant), solving the strong form equation is harder, but still possible. For a 1-D rod with fixed end conditions, a constant distributed body force, b(x) = b_0 = 5 lb/in, and a cross-sectional area defined as A(z) = 5 +2x, the solution for the displaced shape looks like: u(x) = -1/E (1/4C_1 ln (2x+5)+C_2-5x/2) Determine u(x) if both sides of the rod are fixed (u(0) = 0, u(L) = 0) Given the following: E = 20,000ksi, A = 10in^2, L = 20in, b_0 = 5 lb/in, plot your calculated in displacement function in MATLAB Now approximate the solution using matrix/direct stiffness methods. Break the rod into several elements of varying areas and lump the distributed forces as point loads at the nodes. Plot your results on the same plot as Part b Comment on your solution

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