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please solve 18% of all Americans live in poverty. If 31 Americans are randomly selected, find the probability that a. Exactly 4 of them live

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18% of all Americans live in poverty. If 31 Americans are randomly selected, find the probability that a. Exactly 4 of them live in poverty, b. At most 5 of them live in poverty, C. At least 6 of them live in poverty. d. Between 2 and 5 (including 2 and B) of them live in poverty

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