Please solve

2x We are looking to build an open rectangular container, without a cover, having capacity 16 m , with the length of its base equal to twice that of its width, as in the diagram above. The material used for the base costs 20 dollars per square meter, and that used for the walls costs 10 dollars per square meter. We want to minimize cost. a) Give a formula for the volume of such a container, as an expression in the variables a and y in the diagram: Volume = 16 my = (2x^2y) b) Give a formula for the cost of building such a container, as an expression in the variables x and y : Cost = ((40*x^2)+(480/x)) dollars. Now work out how to minimize the cost of the materials. c) What are the dimensions of such a container that minimize the cost of materials? Height of the container = 2.42 Width of the base = 1.82 m FORMATTING: Give the values with an accuracy of at least two decimal places