please solve it.

We roll a four-sided die which has faces numbered 1, 2, 3, 4. Suppose the die is "loaded", so that any particular even-numbered face is one-fifth as likely to land face up as any particular odd-numbered face. If we roll this die twice, what is the probability that sum of numbers showing is at most 4. (sign / means the fraction) 34/36 57/100 36/144 24/100 27/144