Please Solve the following problem by using ARMv8

2.26 [10] <2.7> Translate the following C code to LEGv8 assembly code. Use a minimum number of instructions. Assume that the values of a, b, i, and j are in registers X0,X1,X10, and X11, respectively. Also, assume that register X2 holds the base address of the array D.

 for(i=0; i 
2.27 [5] <2.7> How many LEGv8 instructions does it take to implement the C code from Exercise 2.26? If the variables a and b are initialized to 10 and 1 and all elements of D are initially 0, what is the total number of LEGv8 instructions executed to complete the loop?