Please solve the //TODO statements in C language using variables "a" and "b" and for division, check if the divisor, b is zero (division by zero is not defined). If it is, an appropriate error message should be output instead of a result. For the logarithm operation, you should use the math library's log function, which is the natural logarithm (base e) and check that both operands are positive. If one or both are not positive, output an appropriate error message.

if(choice == 1) {

printf("%f", a + b);

} else if(choice == 2) {

result = a - b;

printf("%f", result);

} else if(choice == 3) {

//TODO: handle this case (multiplication)

} else if(choice == 4) {

//TODO: handle this case (division)

} else if(choice == 5) {

//TODO: handle this case (minimum)

} else if(choice == 6) {

//TODO: handle this case (log_a(b))

} else {

printf("Please input a valid operator next time");

}

return 0;

}