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please use C++ A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun.
please use C++
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29 th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700,1800, etc.), the year must be evenly divisible by 400 ; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600,1712 , and 2016 Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712-leapyear Ex: If the input is: 1913 the output is: 1 \#include using namespace std; int main() \{ int inputYear; bool isLeapYear = false; cin inputYear; /* Type your code here. */ return 0 ; (3) Step by Step Solution
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