please use MATLAB to solve this problem. Thank you.

2. Cylinder Stresses Consider two long cylinders of two different materials where one cylinder fits just inside the other cylinder. The inner radius of the inner cylinder is a = 0.192 in, and its outer radius is b = 0.25 in. The inner radius of the outer cylinder is also b, and its outer radius is c = 0.312 in as shown. When the system is subjected a radial compressive displacement a hoop stress develops at the interface of the two cylinders. This so called hoop stress for both cyliders at the interface wall is given by 0= +B and 02= 2+ B2 where / represents the inner cylinder and 2 represents the outer cylinder. Constants A1, A2, B1, and By are determined by solving the differential equation that governs this problem. This differential equation is not given here, but below is the resulting system of linear equations based on the solution of the mentioned differential equation. 0 b? 1-(1 +") (1 - 0) L 0 0 TAI 0 -52 IBU 0 (1 + v)EE -(1 - vbE/El A2 0 (1 +82) (1 - 1)c B l-UE) where vi = v2 = 0.4 (Poisson's ratio), E1 = 3 x 10psi, E2 = 3.5 x 104 psi (Modulus of elasticity), and U. = 0.01 in (radial compressive displacement). Write an m-file that will solve the above matrix for constants A1, A2, B, and B; and then within the same m-file using this result calculate the hoop stresses 1 and 2 that occur between the cylinder walls. Note that r= b = 0.25 in at the two cylinder wall interface. Intermediate answers: (do not report them in your solution) A1 = 221.95 lb, A2= - 15.01 lb, B = -6020.64 psi B2 = -2229.40 psi