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(Please use the example problem solving solution as reference, it will be below the problem titled 1.6) Hello! Can you provide response to each part
(Please use the example problem solving solution as reference, it will be below the problem titled 1.6) Hello! Can you provide response to each part of the problem by using physics concepts or formulas? Please also provide all math/formula/conceptual steps so that I can check my own work. This question involves Physics Conversions, Center of Mass, Conservation of Energy, Potential Energy, Kinetic energy, Work-energy Theorem, etc.
Example Problem 1.6 (for reference): Center of Mass of the Earth-Moon System Using data from text appendix, determine how far the center of mass of the Earth-moon system is from the center of Earth. Compare this distance to the radius of Earth, and comment on the result. Ignore the other objects in the solar system. Strategy We get the masses and separation distance of the Earth and moon, impose a coordinate system, and use Equation 9.29 with just / = 2 objects. We use a subscript "e" to refer to Earth, and subscript "m" to refer to the moon. Solution Define the origin of the coordinate system as the center of Earth. Then, with just two objects, Equation 9.29 becomes R = " mere + mmm me + mm From Appendix D, me = 5.97 x 10"* kg mm = 7.36 x 10"2 kg I'm = 3.82 x 10% m. We defined the center of Earth as the origin, so re = 0 m. Inserting these into the equation for R gives R = (5.97 x 1024 kg)(0 m)+(7.36 x 1022 kg) (3.82 x 108 m) 5.97 x 1024 kg+7.36 x 1022 kg = 4.64 x 100 m. Significance The radius of Earth is 6.37 x 10 m, so the center of mass of the Earth-moon system is (6.37 - 4.64) x 105 m = 1.73 x 100 m = 1730 km (roughly 1080 miles) below the surface of Earth. The location of the center of mass is shown (not to scale). RCMSearching for exoplanets It might look like the Sun stays still as the planets orbit it even neglecting the Sun's motion around the Milky Way Galaxy but it actually Wobbles. (a) Following the Example Problem [.6 (attached below), nd the center of mass (we call this barycenrer in astronomy) of the Sun Jupiter system, neglecting all other objects in the Solar System. which is a reasonable approximation. Is the baryeenter within the SunStep by Step Solution
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