Please use the values listed above (369.83K, 42.48bar, 0.152, 12atm) and explain/show how you used them. Previous posts used values such as 277 and 360 k and I dont know why as these values were not given. Thanks

- 3. Compressing propane (T. = 369.83 K, P = 42.48 bar, m=0.152 ) to a liquid state is an important process to petroleum engineering and in oil and gas industry. Let us consider pumping propane into a tank maintained at 5 C and expect propane to liquify at a sufficiently high pressure. Assuming the thermodynamic properties of propane vapor and liquid can be well described by van der Waals equation of state, which has been solved to provide compressibility factors in the following table. Calculate fugacity coefficients and $' to determine that 12 atm is the saturation pressure predicted by vdW EOS. P/atm z Z" 10 0.0585 0.837 11 0.0643 0.817 12 0.070 0.795 13 0.0757 0.772