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Back Indefinite Integrals Graded Quiz - 30 min - 10 total points Due Sep 25, 11:59 PM WIB True or false? If the function f is continuous on the interval [a, b], then da (fa f(x) da) - f(2). 1 point True False 2. True or false? If a function f(I) has an antiderivative F(I), then it also has infinitely many other antiderivatives. 1 point O True O False 3. Evaluate the integral. 1 point (274 + v3x +1) da O 225 4 20823/2 + 1 + C O 2x4 + V3al + + C 25+ + +C -24 4 2V/3 3/2 3 23/2 + 2 + C 4. Evaluate the integral 1 point z +1 OF+1+C 01 (12 + 2a + 1) +0 2 (x2 + 2x +1) I + 1 5. Evaluate the integral. 1 point 2 da O er+2 a + c O e2z + C -+ C O er+2 6. Evaluate the integral. 1 point cos(z + 1)da O sin(z + 1) + C O sinc + a + C O sin r + cosa + C O sin z + C 7. Evaluate the integral. 1 point sin - cos ,da [Hint: sin 20 = 2 sin 0 cos 0] O - sina + C O 2 sina + C O - cos z + C O -2 cosa + C 8. Evaluate the integral. 1 point OF +1+In(12 + 1) +C O tan 1(22 + 1) + C OF+1+ tan-1z + C O 373 + r + tan 1(1) + C 9. Evaluate the integral. 1 point O - cos z + C O 2 sin z + C 0_ 1 cos 27 + C O -2 cosa + C 10. Evaluate the integral. 1 point (5x - 57) da 0 5 2 5241 + c 512 _ In5+ 0 5 2 5 % In 5 + C 572_ 5241 Upgrade to submitBack Integration by Substitution Graded Quiz . 30 min - 10 total points Due Sep 25, 11:59 PM WIB 1. Which of the following is the best u-substitution to evaluate the integral 1 point sin? 2: cos 2adz? O u = sin 2x O u = 2x O u = sin 2x O u = cos 2: 2. Evaluate the indefinite integral. 1 point 12 + 3 O - [In(12 +3)12 + C Of In(22 +3) + c O - In(12 +3) +C O H[In(12 + 3)12 + C 3. Evaluate (12 + 3) 20 x da 1 point 38 (72 + 3) 19 + C 0 1 42 (12 + 3)21 + C 0 1 21 (2 + 3)21 + C (72 + 3)21 + C 4. Evaluate the definite integral. 1 point sec(sin z) tan(sin z) cos ada O tan(1) - 1 O tan(1) O sec(1) - 1 O sec(1) 5. What is the area beneath the curve f(I) = 12 V3 - 1 from = = - 2tox = - 1? 1 point 38 2 3 O 2 . 113/2 - 16 This problem cannot be solved. 6. Evaluate the indefinite integral. 1 point sin va di VI O _ cos vi + C VI O -2 cost + C O 2VI cos Vi + C O -2 cos Vi + C 7. Use substitution to evaluate S tan a dr. 1 point O In | cos z| + C O - In | cos z| + C O - In | sin z| + C O In | sin z| + C 8. Evaluate the indefinite integral. 1 point O "(I +2)5/2 - 4(2+2)3/2 + 0 0 2(12 + 22) 3/2 + C O 225/2 - 423/2 + 0 O (I -2)5/2 + 2(2 + 3(2 -2)3/2 + 0 9. Evaluate the indefinite integral. 1 point 21 43 dt In 2 In(2' + 3) + C ing In(24) - 3 + C In 2 + 3 In(2') + c O 2* In(2* + 3) + C 10. Use substitution to evaluate the definite integral Jo (2 + 4) (x - 1)4 dx. 1 point If your answer is not a whole number, enter it as a fraction in lowest terms. Preview will appear here.. Enter math expression here Upgrade to submitBack Integration with Calculators Graded Quiz - 30 min . 5 total points Due Oct 2, 11:59 PM WIB 1. Evaluate (1 + 212)2 dx. 1 point O 2 (14 272 + In |1 + 2a21 +c 4 (14 2x2 + In |1 +22 21 +0 3 (14 272 + In |1 + 2a21 +0 14 27 -2 1 |1 + 2x] + 0 2. Evaluate 4 - el dx 1 point O1 ez - 2 ex +2 + C -In e + 2 + 0 7tan-1 6" 2+0 3. Evaluate V 2y - 3 dy y2 1 point O y' - i +ly + Vy2 -+c 0 -v2\\y2 - 1- 3 2Cos 1 3 +0 O V2y2 - 3-3V/2 cos-1 +C O _V2y2 - 3 + v2ly + Vy -+c Evaluate the definite integral / x2v4 - x2dx. 1 point Enter your answer as a decimla rounded to two places. Enter answer here 5. Evaluate the definite integral / (3x + 1) v2dx. 1 point Enter your answer as a decimal rounded to two places. Enter answer here Upgrade to submitBack Sequences and Series Graded Quiz - 30 min . 10 total points Due Sep 4, 11:59 PM WIB 1. Determine whether the sequence Extra open brace or missing close brace is increasing, decreasing, nor not monotonic. 1 point an = n + 3 decreasing increasing not monotonic 2. Determine whether the sequence {on} is increasing, decreasing, nor not monotonic. point on = 37 3n + 7 not monotonic decreasing increasing Evaluate the limit of the sequence { an } with an = 3 + (-1)" 1 point Oo O 4 O 1 0 3 The series does not converge. Evaluate the limit of the sequence { bn } with bn = n2 + 4n + 5 point (2n - 1)(3n - 1) O 6 The sequence does not converge. O O 3 5. Does the sequence { n } converge or diverge? 1 point converges diverges Find the sum of the finite series (-1)*+1k2 1 point Enter answer here Find an expression for the value of the sum of the geometric series _ ()". a point O1 1-(3)14 33 . 1 1-(3)4 O1 1-(3) 34 .- 0 1 1-(3)1 33 8. Find the sum of the following infinite series. 1 point 48 5+2+ 25 F ... 0 5 3 O 10 O 25 The series diverges. Let S = a an be an infinite series with nth partial sum sn = 7 - -2. 1 poin n=1 What is the value of _ an? If your answer is not a whole number, enter it as a decimal rounded to two places. Enter answer here As before, let S = - Can be an infinite series with nith partial sum on. = 7 - 1 point Find the sum If your answer is not a whole number, enter it as a decimal rounded to two places. Enter answer here Upgrade to submitBack The Definite Integral Due Sep 11, 11:59 PM WIB Graded Quiz - 30 min - 10 total points 1. True or False? A Riemann Sum will always underestimate the true area under a graph. 1 point True False 2. Why does the definite integral of f (I) evaluated from a to b equal the area bound between a curve and the I-axis? 1 point O Integrating the width of the function with respect to the height changes the equation from f (I) to A(I). Integrating the height of the function with respect to the width sums up all the tiny areas created by dividing the area into an infinite number of rectangles. Integrating the height of the function with respect to the width undoes any previous differentiation, which returns you to the equation for area. Integrating the height of the function with respect to the width produces an antiderivative. Antiderivatives are another name for area. Express the integral as a limit of Riemann sums. Do not evaluate the limit. point Him (2+ #)"+247)8 Use a right Riemann Sum with 4 rectangles to approximate 4x2 da. 1 point Enter answer here Use a left Riemann Sum with 3 rectangles to approximate | 4x - 3 da 1 point Enter answer here 6. Use a right Riemann sum with three subintervals of equal length to approximate the area between the I-axis and the graph of f (x) = 7 + 6x - ? for 0 0. Select one function and one number. Of(z) = 21/2 Of(z) = 23/2 Of(z) = 2x 1/2 Of(z) = 23/2 O a= -4 O a=-2 Da=0 O a=4 Upgrade to submit