PLEASE USE VERY NEAT HANDWRITING. YOU DONT HAVE TO SHOW YOUR WORK!!! JUST ANSWERS ONLY!!! AND DO ALL OF THEM !!!and i repeat please only write the answers.
1. [-/6 Points] DETAILS SCALCET9 2.3.001. Given that lim f(x) = 9 lim g(x) = -5 lim h(x) = 0, find each limit, if it exists. (If an answer does not exist, enter DNE.) (a) lim [f(x) + 49(x)] (b) lim, [o(x)]3 (c) lim v R(x) (d) lim 5f(x) x-3 g(x) (e) lim g(x) x -3 h(x) (f) lim 9(x)h(x) F(x ) Need Help? Road It Watch It2. [-/6 Points] DETAILS The graphs of fand g are given. Use them to evaluate each limit, if it exists. (If an answer does not exist, enter DNE.) y= f( x) =g(x) (a) lim [f(x) + g(x)] (b) lim [f(x) - g(x)] (c) lim [f(x)g(x)] (P) lim (43 g(x) (e) lim [x26(x)] (F) f(-1) + lim g(x)3. [-/1 Points] DETAILS SCALCET9 2.XP.3.005. Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) t* - 2 lim 2+- - 3t + 3 Need Help? Read It Watch It Submit Answer 4. [-/1 Points] DETAILS SCALCET9 2.XP.3.006. Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) lim Vu* + 3u + 3 Need Help? Read It Watch It5. [-/1 Points] DETAILS SCALCET9 2.XP.3.007. Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) lim (1 + x) (5 - 5x2 + *3) Need Help? Read It Watch It 6. [-/2 Points] DETAILS SCALCET9 2.3.010. (a) What is wrong with the following equation? x2+ x - 42 =x+ 7 x - 6 O ( x - 6 )(x + 7) # x-+x- 42 O The left-hand side is not defined for x = 0, but the right-hand side is. O The left-hand side is not defined for x = 6, but the right-hand side is. O None of these - the equation is correct. (b) In view of part (a), explain why the following equation is correct. lim x2 + x - 42 = lim (x + 7) - 6 X - 6 O Since x- + x - 42 = and x + 7 are both continuous, the equation follows. * - 6 Since the equation holds for all x # 6, it follows that both sides of the equation approach the same limit as x - 6. This equation follows from the fact that the equation in part (a) is correct. O None of these - the equation is not correct.7. [-/1 Points] DETAILS SCALCET9 2.XP.3.014. Find the limit. (If an answer does not exist, enter DNE.) +2 - 36 lim t--6 2+2+ 13t + 6 Need Help? Road It Watch It Submit AnswerEvaluate the limit, if it exists. (If an answer does not exist, enter DNE.) u+ 3 1--3 03+ 27 Need Help? Read It Watch It 9. [-/1 Points] DETAILS SCALCET9 2.3.023. MY NOTES PRACTICE ANOTHER Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) lim V 64 + h - 8 h Need Help? Read It Watch It 10. [-/1 Points] DETAILS SCALCET9 2.3.029. MY NOTES PRACTICE ANOTHER Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) 3 - VX lim 9x - x11. [-/6 Points] DETAILS SCALCET9 2.3.037. MY NOTES PRACTICE ANOTHER A graphing calculator is recommended. Use the Squeeze Theorem to show that lim x2 cos(22nx) = 0. Illustrate by graphing the functions R(x) = -x2, g(x) = x2 cos(221x), and h(x) = x on the same screen. Let f(x) = -x , g(x) = x" cos(22nx), and h(x) = x2. Then [? v s co=(2201x) = [? v) = [? v sx co=(22nx) = [? v ) . Since lim f(x) = lim h(x) = , by the Squeeze Theorem we have lim g(x) = Need Help? Read It Watch It 12. [-/1 Points] DETAILS SCALCET9 2.3.025. MY NOTES PRACTICE ANOTHER Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) lim X - Need Help? Read It Watch It13. [-/1 Points] DETAILS SCALCET9 2.XP.3.011. MY NOTES PRACTICE ANOTHER Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) 2 + 4x lim 5+ 2x2+ 5x4 Need Help? Read It Watch It 14. [-/1 Points] DETAILS SCALCET9 2.XP.3.004. MY NOTES PRACTICE ANOTHER Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) lim v 4 - x2 x - 2 Need Help? Read It Watch It
