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Please verify my answers. Q2. Test a hypothesis with bivariate regression. Suppose a researcher wishes to use the same data set from Q1 to answer

Please verify my answers.

Q2. Test a hypothesis with bivariate regression.

Suppose a researcher wishes to use the same data set from Q1 to answer the following question:

Can the average number of years adults have spent in schooling in a state significantly predict crime rate in that state?

A. What is the null hypothesis being tested for this research question?

H0: The average number of years adults have spent in schooling in a state does not significantly predict the crime rate in that state.

Or ???

H0: There is no significant relationship between the average number of years adults have spent in schooling and the crime rate in a state. ???

B. Show a scatterplot with the outcome variable on the Y-axis. (Note: In SPSS, select "Legacy Dialogs" at the bottom of the "Graphs" menu. Choose "Scatter/Dot" and "Simple Scatter.") [Paste the scatterplot here.]

C. Examine the scatterplot. Is there a hint of a linear relationship? How do you know?

The scatterplot shows a negative linear relationship between education and crime rates. As education increases, crime rates decrease, which suggests that the more years adults spend in school, the less likely they are to commit a crime.

Below is the SPSS output table for a test of the regression model (omnibus test).Use the information in this table to answer the questions in D and E.

Model Summaryb

Model

R

R Square

Adjusted R Square

Std. Error of the Estimate

Change Statistics

R Square Change

F Change

df1

df2

Sig. F Change

1

.531a

.282

.266

33.5409

.282

17.645s

1

45

<.001

a. Predictors: (Constant), Education

b. Dependent Variable: Crime Rate

D. Is theregression model statistically significant? Explain your answer. In other words, what does statistical significance or non-significance mean in this context?

Yes, the regression model is statistically significant. The significance (p-value) = <0.001, which is less than 0.05. In this context, the statistical significance means that we can reject the null hypothesis and state that the coefficient is statistically different from zero.

E. How much of the variance in the outcome variable is accounted for by the predictor variable in this model?

The variance in the outcome variable accounted for by the predictor variable in this model is 26..6% (Adjusted R Square = 0.266).

OR

Is it ( 0.282 = R square Change) = 28.2% ???

Below is the output table for the coefficients. Use the information in this table to answer the questions in F - I.

Coefficientsa

Model

Unstandardized Coefficients

Standardized Coefficients

t

Sig.

B

Std. Error

Beta

1

(Constant)

298.627

47.053

6.347

<.001

Education

-17.286

4.115

-.531

-4.201

<.001

a. Dependent Variable: CrimeRate

F. What is the linear equation (i.e., the equation for the prediction line) formed by the unstandardized coefficients?

= a + bx

CrimeRate: = 298.627-17.286x (Education)

Constant: 298.627: Slope: 17.286: Predictor variable: Education

G. What is the standardized coefficient for the predictor variable?

-.531

H. Should the researcherreject orfail to reject the hypothesis? Explain how you arrived at your answer.

Since the p-value of <.001 is less than 0.05, the researcher should reject the null hypothesis. This indicates that there is a statistically significant relationship between the predictor and the outcome variable.Moreover, the T value for schooling is -4.201, indicating a statistically significant result. The likelihood of randomly observing such a significant correlation between education and crime rate is exceedingly small. Thus, the researcher can reject the null hypothesis that there is no relationship between education and crime rate. Contrary to the null hypothesis, the data suggests that as education increases, crime rates decrease (negative correlation between education levels and crime rates).

I. Complete the table. States 48, 49, and 50 have the average schooling in years (Education) as listed below in the table. Use the linear equation found in (F) to estimate the crime rate in those states. You must show your work (the values placed into the equation to make the prediction).

State Education Prediction Equation Estimated Crime Rate
48 12.2 =298.627-17.286*12.2 87.7378
49 11.5 =298.627-17.286*11.5 99.838
50 13.8 =298.627-17.286*13.8 60.0802

CODE BOOK

Variable Description Values
Q1Q2
CrimeRate Number of offences per million people Crime count
Education Average number of years of schooling number of years
Expenditure Police expenditure per capita on police (in thousands) number of thousands
YouthUnemploy Number of males unemployed aged 18-24 per 1000 number of people
MatureUnemploy Number of males unemployed aged 25-39 per 1000 number of people
BelowWage Poverty rate; Number of families below half the average wage per 1000 number of families
CrimeRate Category Classification of crime by crime rate LOW CRIME crime rate of 0 - 76.6 1
LOW AVERAGE CRIME crime rate of 76.6 - 103.5 2
HIGH AVERAGE CRIME crime rate of 103.6 - 130.3 3
HIGH CRIME crime rate130.4 - 179.2 4
DomPolit Dominant Political Party: The majority of the populace in the state voted for the specified party in all major elections over the past 2 years. DEM democratic 1
REP republican 2

DATA SET

State CrimeRate Education Expenditure YouthUnemploy MatureUnemploy BelowWage CrimeRate Category DomPolit
1 26.5 11.1 75 80 21 123 LOW CRIME DEM
2 36.9 12.9 54 136 39 210 LOW CRIME REP
3 37.1 12.2 44 98 33 256 LOW CRIME REP
4 42.7 10.8 41 101 50 235 LOW CRIME DEM
5 45.7 11.2 97 79 24 162 LOW CRIME DEM
6 47.9 12.8 60 81 24 199 LOW CRIME DEM
7 50.6 13.1 57 71 29 176 LOW CRIME REP
8 52.9 12 63 119 21 168 LOW CRIME REP
9 61.8 14.1 54 110 22 126 LOW CRIME DEM
10 69.4 12.2 47 97 28 215 LOW CRIME REP
11 72.4 12.1 44 93 36 247 LOW CRIME DEM
12 75.4 13.4 87 112 34 146 LOW CRIME REP
13 77.3 12.7 61 95 28 189 LOW AVERAGE CRIME REP
14 79.6 12.3 115 82 33 127 LOW AVERAGE CRIME DEM
15 80.6 11.2 54 76 25 246 LOW AVERAGE CRIME DEM
16 82.2 11.9 68 104 25 213 LOW AVERAGE CRIME REP
17 87.5 12.9 67 107 34 199 LOW AVERAGE CRIME REP
18 92.9 13 128 80 39 140 LOW AVERAGE CRIME REP
19 94.1 10.9 81 106 35 162 LOW AVERAGE CRIME REP
20 95.2 10.1 56 110 36 254 LOW AVERAGE CRIME DEM
21 97.8 12 53 92 41 243 LOW AVERAGE CRIME DEM
22 99.9 11 70 80 28 321 LOW AVERAGE CRIME REP
23 102.4 10.5 54 84 32 249 LOW AVERAGE CRIME REP
24 103.5 11.9 56 79 28 257 LOW AVERAGE CRIME REP
25 104.5 11.7 71 87 28 182 HIGH AVERAGE CRIME DEM
26 105.4 10.4 91 119 41 159 HIGH AVERAGE CRIME REP
27 107.8 10.2 62 99 29 243 HIGH AVERAGE CRIME DEM
28 110.1 12.9 66 87 45 151 HIGH AVERAGE CRIME REP
29 111.5 10.8 97 103 34 160 HIGH AVERAGE CRIME DEM
30 113.5 11.3 115 93 35 175 HIGH AVERAGE CRIME DEM
31 116.3 10.7 77 117 51 256 HIGH AVERAGE CRIME DEM
32 118.7 10.9 79 99 43 170 HIGH AVERAGE CRIME REP
33 124.5 8.1 73 143 41 177 HIGH AVERAGE CRIME DEM
34 127.8 11 96 115 36 132 HIGH AVERAGE CRIME REP
35 129.8 10.9 157 93 47 169 HIGH AVERAGE CRIME DEM
36 130.7 10 64 73 60 220 HIGH CRIME DEM
37 133.5 10.8 74 89 36 230 HIGH CRIME REP
38 134.6 9.9 83 83 56 234 HIGH CRIME DEM
39 137.5 9.8 76 120 41 204 HIGH CRIME DEM
40 140.5 11.5 105 131 61 174 HIGH CRIME DEM
41 142.7 10.2 101 94 58 180 HIGH CRIME DEM
42 152.6 13 98 88 38 151 HIGH CRIME REP
43 157.3 10.1 109 82 50 312 HIGH CRIME REP
44 162.7 11 95 97 45 196 HIGH CRIME DEM
45 165.6 11 116 79 42 172 HIGH CRIME DEM
46 177.2 9.8 141 110 60 169 HIGH CRIME REP
47 179.2 10.2 143 190 67 150 HIGH CRIME DEM

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