please WRITE all equations used and circle final answer. draw diagrams and use equations covered in work, energy, and momentum.

1. a bomb at rest explodes, breaking into three pieces. Two of the pieces have equal mass and first one fly off with speed of 80 m/s to 48 NE, and second piece fly off with speed of 100.0 m/sec to 35 NW. The third pieces have two times the mass of each other piece. What are the magnitude and the direction of the third piece immediately after the explosion?(Apply conservation of momentum in two dimension)

2. a 1800 kg elevator cabin is 80.0 m above a heavy-duty spring when the cable holding the cabin breaks. The cabin hits the spring and compress the spring to 40 cm. What is the spring constant of the spring?(apply conservation of Energy)

on Date: 20 Tus Wed Page No.: In vertical direction ( N-S direction ) m xbox Cos ( 35 ) + m x 80 los ( 48 ) = M. V lose 4 2 Now, both equation's become as VSing = - 9. 752 m/be -( D) V lose = 67. 71 m / Sec - - (2 2 Dividing ( by 3 , we get tance = 0.143 hance 9 = 8:172 Degrees V z 68 . not mflex. ( By sipstituting 09 = 8-172 in any one of equations . above ) - 8.172 Degree 68 - 407 mesecProttext Mon Date 20 The Tue Fri Wed Page No.: Sat In this question first we will find out the mass of individual particle . As given bomb of mass in splits into three particles two of equal mass let be and theuds with double the mass of previous part hence (2 x NOOLD SCtxt2x = m } total mass should Us = m beequal to original J ( = M/ 2 x = m mass 3 2 given the direction and velocity of masses X are . N 35 m / sec Bom bee . 350 E Now let mass 22 - M let will fly in disection quen in figure above ? with velocity vmfee Now as initially bomb is at rest is momentum is zero, hence the net momentum should be zero In - x- direction . ( E - w direction ) 100 . m Sin ( 35 ) - my 80 Sin ( us ) = musing 4 2