Pls do all parts thx.

1 function (L,U- LUDecomp (A) dim-size(): n = dp (1) 2- 3 - 4 5 115 - 16 17 Identity matrix to keep the score" I = eye (nl) 7 8 Reduce A to row echelon form 9- for 1 - 1:n-1 The column 10- for 1-A The row 11- alpha B The magenta numbers in video. 12- Ali, :) A (1, - alpha A (), :): Do the row operation to A. 13 - I() = Skeep track of the row operation. 14- end end 1- Define the reduced A as U and I as L. 18 U - A; L-I: Write out this code and use the function to answer the following questions. Important: you should only submit information that is asked of you in the question. Do not submit your MATLAB files or copies thereof. (a) What are the three missing rows A, B and C? Write them in your submission and also include them in your completed code to help you answer the proceeding questions (but do not submit your full code, it is enough to submit only the missing parts A, B and C). (b) Use the function to find the LU decomposition of a 6 x 6 matrix containing just l's and O's where I's are on the leading diagonal as well as the first and third diagonals to the right as well as the third and fourth diagonals to the left (note if you have entered the correct matrix and part (a) is correct your LU decomposition should contain only integers). To be clear, A - 6x6 1 1 1 @ 1 @ @ 1 1 1 @ 1 1 1 1 1 1 1 0 0 1 11 1 1 In your answer, just tell us what your output Land U are, no other working is needed. (C) Using pen and paper (showing working) and your computed LU decomposition from part (b), use forward and back substitution to find the solution vector x to Ax = b, where b = (1.0, 0, 0, 0, 0]", in terms of the arbitrary scalars u and u. (d) Now use your code and attempt to find the LU decomposition of the 6 x 6 matrix formed by writing numbers 1 to 6 on the first row, 7 to 12 on the second row, and so on. A = 4 5 11 1 7 13 19 25 31 2 a 14 20 3 9 15 21 27 33 10 16 22 28 34 17 23 29 35 6 12 18 24 30 36 26 32 Investigate the response of MATLAB to this input. Briefly explain in words what is going on here and why the function fails. It may be useful to know that "NaN' in MATLAB means "Not a Number' and often arises when you are attempting to divide a number by zero. 1 function (L,U- LUDecomp (A) dim-size(): n = dp (1) 2- 3 - 4 5 115 - 16 17 Identity matrix to keep the score" I = eye (nl) 7 8 Reduce A to row echelon form 9- for 1 - 1:n-1 The column 10- for 1-A The row 11- alpha B The magenta numbers in video. 12- Ali, :) A (1, - alpha A (), :): Do the row operation to A. 13 - I() = Skeep track of the row operation. 14- end end 1- Define the reduced A as U and I as L. 18 U - A; L-I: Write out this code and use the function to answer the following questions. Important: you should only submit information that is asked of you in the question. Do not submit your MATLAB files or copies thereof. (a) What are the three missing rows A, B and C? Write them in your submission and also include them in your completed code to help you answer the proceeding questions (but do not submit your full code, it is enough to submit only the missing parts A, B and C). (b) Use the function to find the LU decomposition of a 6 x 6 matrix containing just l's and O's where I's are on the leading diagonal as well as the first and third diagonals to the right as well as the third and fourth diagonals to the left (note if you have entered the correct matrix and part (a) is correct your LU decomposition should contain only integers). To be clear, A - 6x6 1 1 1 @ 1 @ @ 1 1 1 @ 1 1 1 1 1 1 1 0 0 1 11 1 1 In your answer, just tell us what your output Land U are, no other working is needed. (C) Using pen and paper (showing working) and your computed LU decomposition from part (b), use forward and back substitution to find the solution vector x to Ax = b, where b = (1.0, 0, 0, 0, 0]", in terms of the arbitrary scalars u and u. (d) Now use your code and attempt to find the LU decomposition of the 6 x 6 matrix formed by writing numbers 1 to 6 on the first row, 7 to 12 on the second row, and so on. A = 4 5 11 1 7 13 19 25 31 2 a 14 20 3 9 15 21 27 33 10 16 22 28 34 17 23 29 35 6 12 18 24 30 36 26 32 Investigate the response of MATLAB to this input. Briefly explain in words what is going on here and why the function fails. It may be useful to know that "NaN' in MATLAB means "Not a Number' and often arises when you are attempting to divide a number by zero