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Part 10 of 10 - Going Further: Switching Polarity, Part1 The partners now consider the same three capacitors in parallel, c1 = 1.30 \"F, C2 = 2.00 HF, and c3 = 9.75 in: initially connected to a potential difference of AVb = 20.0 v. Kylie suggests removing the battery and removing and replacing C2, this time with positive and negative sides switched. The capacitors form an isolated system with the same capacitance as before. She asks Blake how he can determine the new potential difference across the capacitor combination. What is his response? 'Because the system is isolated, Qnew = Q1 Q2 + Q3, and because Q = CAv, Qnew = (C1 + C2 + C3)AV. Solve this for AV." "Because C2 is reversed, the charge on it is zero, and because Q = CAV, Q = (C1 + C3)AV. Solve this for AV." new "Because the system is isolated, Qnew = Q1 QZ Q3, and because Q = CAV, Qnew = (C1 + C2 + C3)AV. Solve this for AV." "Because C2 is reversed, the charge on it is twice the original charge, so Qnew = (C1 + 2C2 + C3)AV. Solve this for AV." Blake is correct. The charge will rearrange itself so that the potential difference across each capacitor is equal. Going Further: Switching Polarity, Part 2 Blake challenges Kylie to calculate the new voltage. What is the new voltage? :]V :0\" Now Gavin and Maya try a homework problem. Three capacitors of capacitance C1 = 3.15 11F, C2 = 2.65 11F, and C3 = 6.45 [1F are connected in series. A potential difference of AVb = 92.0 V is maintained by a battery. Find the equivalent capacitance of the series of capacitors and the charge on each capacitor. Ceq = 1.177 ,uF Q = x Your response differs from the correct answer by more than 10%. Double check your calculations. 11C Determine the effect on the equivalent capacitance of reducing the second capacitance to 0.1 times its previous value. Ceq = 1.1761 x Your response differs from the correct answer by more than 100%. 11F Part 7 of 8 - Analyze Now the friends try a homework problem. A capacitor is constructed with two parallel metal plates each with an area of 0.63 m2 and separated by d = 0.80 cm. The two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each of the oppositely charged plates. Find the electric eld in the region between the two plates. 625 ./ V/m Find the charge Q. 0697 x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. C Find the capacitance of the parallel plates. 3.485 x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. x 10'6 F 4. [0.5/1 Points] DETAILS PREVIOUS ANSWERS SERPSE10 25.1.P.002. MY NO Two conductors having net charges of +16.0 JC and -16.0 JC have a potential difference of 16.0 V between them. (a) Determine the capacitance of the system. 0.000001 F (b) What is the potential difference between the two conductors if the charges on each are increased to +256.0 JC and -256.0 JC? 272.0 X What is the relationship between capacitance, charge and potential difference? V12. [05/1 Points] PREVIOUS ANSWERS SERPSE10 25.3.0P.011.M|.NVA ASK YOUR TEACHER | PRACTICE AN( Consider the circuit shown in the gure below, where C1 = 8.00 pF, C2 = 6.00 uF, and AV = 22.0 V. Capacitor C1 is first charged by closing switch 51. Switch 51 is then opened, and the charged capacitor connected to the uncharged capacitor by closing 52. + cl 62 AV -[/o:]:/I SI S2 (D (a) Calculate the initial charge (in uC) acquired by C1. (Round your answer to at least one decimal place.) 176 v uc (b) Calculate the final charge (in pC) on each capacitor. (Round your answers to at least the nearest integer.) Q1 = 175.0 x When switch C1 is closed, some charge will move from this capacitor to C2. uC Q2 = 75.4 uc (c) What If? After a very long time, switch S1 is also closed. By what amount does the charge on the second capacitor change after 51 has been closed for a very long time? (Give your answer in uC.) 0000069693 x \"C