Pls handwritten and correct

PX ol fix) be thrice diff. fo satisfying the condition flo = f (6 - 20) # x E [0, 6 ] and f ' (0) = t' ( 21 = f' ( 5 )= 0 find the minimum number of zeroes of 9120) = 1" (202 + f'(30 8"(2) = 0 in X E [0 , 6 ]