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Point number Time of fall from beginning (s) Distance of fall (cm) Change in distance (cm) Velocity (cm/s) = Change

Plot a graph of the distance of the fall (y) versus the time of fall (t). Find the value of acceleration due  
 

Point number

Time of fall from beginning

(s)

 

Distance of fall

(cm)   

 

Change in distance (cm)

 

 

Velocity (cm/s) = Change in distance/ time for each interval 

10.0000.00________________________ 
20.0171.501.501.50/ (1/60) = 90
30.0333.301.801.80/ (1/60) = 108
40.0505.30  
50.0677.60  
60.08310.20  
70.10013.10  
80.11716.20  
90.13319.70

 

 

 

 

100.15023.40

 

 

 

 

110.16727.40

 

 

 

 

120.18331.60

 

 

 

 

130.20036.10

 

 

 

 

140.21740.80

 

 

 

 

150.23345.80

 

 

 

 

160.25051.10

 

 

 

 

170.26756.70

 

 

 

 

180.28362.50

 

 

 

 

190.30068.70  
200.31775.00  
210.33381.70  

Plot a graph of the distance of the fall (y) versus the time of fall (t). Find the value of acceleration due to gravity from the best fit line/curve. You need to type the x-axis values in the first column and the y-axis values in the second column in a Microsoft Excel spreadsheet to plot the graph correctly. Please include the graph with the lab report. Plot a graph of the average velocity (av) versus the time of fall (t). Find the value of acceleration due to gravity from the best fit line/curve. Please include the graph with the lab report. Find the average values of the acceleration due to gravity calculated from these two graphs. This is the experimental value of the acceleration due to gravity. Experimental value for the acceleration due to gravity. cm/s

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